Vp=2
Vdc=50
r=Vrms/Vdc
Vrms=Vp/1.121
so r=0.028
The RMS value of an AC voltage is VRMS = VPEAK / sqrt(2), where VPEAK = the voltage peak to neutral.AnswerThe average value of a sinusoidal a.c. voltage is zero.
A: AC or our line voltage is sinusoidal in nature it goes up to a positive peak returns to zero and proceed to the negative peak. 120V AC is actually swinging from peak to peak. It is 120 volts but the peak is the 120 v times 1.41 or 169.2 volts and since it also go negative then the peak to peak 120 volts times 2.82 or 338.40 volts or twice the peak voltage
Ripple factor (γ) may be defined as the ratio of the root mean square (rms) value of the ripple voltage to the absolute value of the dc component of the output voltage, usually expressed as a percentage. However, ripple voltage is also commonly expressed as the peak-to-peak value. This is largely because peak-to-peak is both easier to measure on an oscilloscope and is simpler to calculate theoretically. Filter circuits intended for the reduction of ripple are usually called smoothing circuits.The simplest scenario in ac to dc conversion is a rectifier without any smoothing circuitry at all. The ripple voltage is very large in this situation; the peak-to-peak ripple voltage is equal to the peak ac voltage. A more common arrangement is to allow the rectifier to work into a large smoothing capacitor which acts as a reservoir. After a peak in output voltage the capacitor (C) supplies the current to the load (R) and continues to do so until the capacitor voltage has fallen to the value of the now rising next half-cycle of rectified voltage. At that point the rectifiers turn on again and deliver current to the reservoir until peak voltage is again reached. If the time constant, CR, is large in comparison to the period of the ac waveform, then a reasonably accurate approximation can be made by assuming that the capacitor voltage falls linearly. A further useful assumption can be made if the ripple is small compared to the dc voltage. In this case the phase angle through which the rectifiers conduct will be small and it can be assumed that the capacitor is discharging all the way from one peak to the next with little loss of accuracy.[1]
The average voltage is the rms voltage.Volts peak = volts RMS times 1.414Volts RMS = volts peak times 0.7071Use the link below to an RMS voltage, peak voltage and peak-to-peak voltage calculator.********************************The average voltage is not the r.m.s. voltage.The average voltage of a sine wave is 0.636 x the peak value. Conversely, peak voltage is 1.57 the mean or average.
A load loss factor, LLF,not loss load factor,Êis a calculation used by electrical utility companies to measure energy loss.Ê Its the ratio of average load loss to peak load loss.
Most true RMS voltmeters can measure the value of a ripple voltage on top of a DC supply, when you place it in AC mode. You can also place a small capacitor in series with a DC voltmeter and that would measure the ripple. The real way to do this, because ripple voltage is not sinusoidal, is to use an oscilloscope, particularly if you want the peak values.
Usually with an oscilloscope which shows a graph of the voltage, and then the peak-to-peak ripple voltage can be read off the screen.
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
RMS means root mean square of a sinusoidal wave form and the number that describe it is .741 of the peak average is ,639 of the peak
The defination of form factor is FF=RMS/avg(abs(f(t))) for sin waveform RMS=0.707*peak(f) avg(abs(f(t)))=2/pi*peak(f) so FF=0.707/(2/pi)=1.1106
They are the same thing.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
General formula: square root of the square modulus averaged over a period:xRMS =1/T sqrt( integral (|x(t)|2dt) ) ,where x(t) is the signal and T is its period.If you solve it for sinusoidal waves, you get a 1/sqrt(2)~0.707 factor between peak amplitude and RMS value:xRMS ~ 0.707 XPK ~ 0.354 XPK-PK ~ ...
The RMS value of an AC voltage is VRMS = VPEAK / sqrt(2), where VPEAK = the voltage peak to neutral.AnswerThe average value of a sinusoidal a.c. voltage is zero.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
A: AC or our line voltage is sinusoidal in nature it goes up to a positive peak returns to zero and proceed to the negative peak. 120V AC is actually swinging from peak to peak. It is 120 volts but the peak is the 120 v times 1.41 or 169.2 volts and since it also go negative then the peak to peak 120 volts times 2.82 or 338.40 volts or twice the peak voltage
RMS power is Peak-To-Peak power divided by the square root of 2.This definition, however, only holds true for a non-reactive, or resistive, load, with a power source that is truly sinusoidal.