The defination of form factor is
FF=RMS/avg(abs(f(t)))
for sin waveform
RMS=0.707*peak(f)
avg(abs(f(t)))=2/pi*peak(f)
so
FF=0.707/(2/pi)=1.1106
General formula: square root of the square modulus averaged over a period:xRMS =1/T sqrt( integral (|x(t)|2dt) ) ,where x(t) is the signal and T is its period.If you solve it for sinusoidal waves, you get a 1/sqrt(2)~0.707 factor between peak amplitude and RMS value:xRMS ~ 0.707 XPK ~ 0.354 XPK-PK ~ ...
If the AC signal is sinusoidal, then the RMS value is 141 divided by square root of 2, i.e. 99.7 volts.
The peak value of a sinusoidal ac signal is RMS voltage divided by 0.707, or two times the square root of two. Note: AC signals are rarely truly sinusoidal, because power supplies rarely pull a consistent load for the full duty cycle. (They pulse.) This introduces harmonics in the signal, which cause error in the above calculation but, unless the harmonics are extreme, the calculation is close.
The most common ways are:Mechanically, by placing a coil in a rotating magnetic field, or a rotating coil in a fixed magnetic field. This is how AC power is generated.Electronically, using an oscillator circuit. This is how sinusoidal waveforms are produced in all sorts of electronic equipment.
AC-1This applies to all AC devices (Resistive loads) with a power factor of at least power factor of 0.95 AC-3This applies to AC Inductive loads. Like squirrel cage motors.
I m confuse in ques. Plz chng thd ques.
If its a triangular wave, its not DC, its AC, its just not sinusoidal. Can a transformer operate on triangular AC? Yes, but not as efficiently as on sinusoidal AC.
AC voltage is varying because it is sinusoidal in nature
First rectify the voltage signal then pass it through galvanometer. its reading will give the rms value, so multipy it with form factor to get amplitude of the signal. Form factor for sinusoidal half wave and full wave are 1.11 and 2.22 respectively. One should also take care of voltage drop accross the rectifier diodes in calculation.
Either sinusoidal, or can always be represented as a sum of sinusoids.
I already have the graph drawn on graph paper with 2 waves on , my phase shift is 1.5 and 180degrees. Anyone know how to add and subtract the sinusoidal ac waveforms on the graph, and by phasor diagram?
AC generators have a varying waveform which is sinusoidal in nature, whereas a DC output is linear.
Transformer is based on the principal of mutual inductance.Induction is produced due to sinusoidal wave form thats why we use Alternating current inspite of Direct current.
AC generators have a varying waveform which is sinusoidal in nature, whereas a DC output is linear.
ac
What is a sinusoidal wave? This is a wave that appears to have curves. AC current/voltage. If you see a wave on a ossiloscope of what our AC (Alternating current) mains voltage that will be the answer to the question. DC (direct current) does not appear to have the same qualitys
General formula: square root of the square modulus averaged over a period:xRMS =1/T sqrt( integral (|x(t)|2dt) ) ,where x(t) is the signal and T is its period.If you solve it for sinusoidal waves, you get a 1/sqrt(2)~0.707 factor between peak amplitude and RMS value:xRMS ~ 0.707 XPK ~ 0.354 XPK-PK ~ ...