If the AC signal is sinusoidal, then the RMS value is 141 divided by square root of 2, i.e. 99.7 volts.
the answer is A effective
30 volts provided zero crossing is at midpoint.
peak
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
you take the peak voltage and divide it by the square root of 2 100/1.414= 70.7 volts rms This is true only for sine wave. For other waveforms like a triangle signal it is different.
4V peak to peak
200 volts peak-to-peak is 100 volts peak, which is 70.7 volts rms (standing for root-mean-square) also called "effective". This 70.7 volts is the DC voltage with the same heating power as the peak-to-peak. The relationship is: rms (aka RMS) equals peak-to-peak divided by 2, then divided again by square-root of 2 (1.414). The division by 2 gets us from peak-to-peak to just peak. The next division takes us to rms. If you get an AC voltrage with no description, for exmple 120 volts AC, it is RMS (effective). The USA AC standard supply voltage is 120 (also called 117) volts RMS. The USA peak is 117 x 1.414 (square root of 2) = 165 volts peak, = 330 volts peak-to-peak.
To determine the amplitude of a sinusoidal signal, we look at the peak value of the signal function. The amplitude is the half of the peak-to-peak value of the signal, or the absolute value of the maximum value of the signal.
To convert from Vac (Volts alternating current) to Vp (Volts peak), you can use the formula Vp = Vac * √2. This accounts for the peak value of an AC signal being √2 times the RMS value. Simply multiply the Vac value by √2 to get the equivalent Vp value.
the answer is A effective
I am assuming you're referring to AC voltage and that the 280 volts are peak-to-peak. In such a case, the effective voltage would be 280 divided by the square root of 2. sqrt(2) ~ 1.414 280/1.414 = 198.02 volts This is also called the rms (Root Mean Square)
30 volts provided zero crossing is at midpoint.
Peak - neutral for 120 volts RMS is 169 volts, or 120 * sqrt(2) Peak to peak will be 2 x this value, or 339 volts.
You have not provided enough information. For 12 volt peak to peak, purely AC signal, there will be no DC (hence purely AC). This means there is no offset - the AC signal peaks at 6 volts and -6 volts. The RMS value of this is VRMS = peak / sqrt(2) = 6 / 1.4.
If the Peak to neutral voltage is 220 volts, the root mean square voltage is 155.6 volts (sqrt(220)).
A: AC or our line voltage is sinusoidal in nature it goes up to a positive peak returns to zero and proceed to the negative peak. 120V AC is actually swinging from peak to peak. It is 120 volts but the peak is the 120 v times 1.41 or 169.2 volts and since it also go negative then the peak to peak 120 volts times 2.82 or 338.40 volts or twice the peak voltage
the amlitude of the input signal 10 volt peak to peak was set at 10 khz