Yes, there is a pOH value in acidic solutions which is above 7.0 at the temperature of 298 K.
It will have a pOH of 12. Because pH+pOH=14
First u need to know the pH of sulfuric acid: ph= -log[h+] =-log[0.4] 0.3979 now u can find out the POH of sulfuric acid ph+poh=14 poh=14-0.3979 poh=13.6
That is a base.
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
The pH of a solution can be found using the formula pH + pOH = 14. In this case, if the pOH is 8.7, the pH would be 14 - 8.7 = 5.3.
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pH + pOH =14
The pOH is 6,4.
1.8
The pOH is 8,7.
3
If a strong acid is mixed with a weak base, pH=pKa+/-1 in the buffer region.Corrected:If a strong base is mixed with a weak acid pOH= pKb +/-1 ( pH=(14 - pKb)+/-1) in the buffer region[Remember: For one conjugated pair of weak acid (a = HB) AND its weak base (b = B-):pKa + pKb = 14.0andpH + pOH = 14.0