Yes it is anionic compound because,
We know that the alkali metal sodium (Na) will form an ionic bond with the halogen bromine (Br) to create sodium bromide (NaBr). The equation looks like this:Na + Br => NaBr
The compound sodium bromide is formed by the formation of ionic bonds between sodium and bromide ions.
Generally a metal with a nonmetal forms an ionic bond. Sodium is a metal and bromine is a nonmetal, so they will form an ionic bond, forming the compound sodium bromide, NaBr.
NaBr is an ionic compound. Generally, a metal bonded with a nonmetal forms an ionic compound. Also, the difference in electronegativity between Na and Br is 2.03, which is definitely ionic.
It is an ionic bond because sodium is a metal and bromine is a nonmetal.
I'm not sure but I know that when sodium reacts with bromine it does that.
Sodium Bromide - ionic compound - NaBr.
The compound sodium bromide is formed by the formation of ionic bonds between sodium and bromide ions.
Generally a metal with a nonmetal forms an ionic bond. Sodium is a metal and bromine is a nonmetal, so they will form an ionic bond, forming the compound sodium bromide, NaBr.
NaBr is an ionic compound. Generally, a metal bonded with a nonmetal forms an ionic compound. Also, the difference in electronegativity between Na and Br is 2.03, which is definitely ionic.
It is an ionic bond because sodium is a metal and bromine is a nonmetal.
I'm not sure but I know that when sodium reacts with bromine it does that.
Bromine (molecular Br2) is an covalent compound
NaBr is Sodium Bromide (Na is Sodium, Br is Bromine) Usually when you link only two elements together the ending of the product is -ide
YES!!! 2Rb(s) + Br2(l) = 2RbBr(s) It is similar to the sodium / chlorine reaction, and compound.
If a compound contains at least one metal atom and at least one nonmetal atom, the compound is ionic. Na (Sodium) is a metal. Br (Bromine) is a nonmetal. Therefore, the compound NaBr is ionic.
ionic
yes sodium iodide is an ionic compound