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Not exactly ... notice that it doesn't make sense to say that

an acceleration is equal to a speed.

The event horizon is the distance at which the escape velocity

is equal to the speed of light.

That's the square root of [ 2 (gravitational constant) (central mass)/(distance from its center) ] ===========================

I never played much with this before. But you asked, and I did, and

I thought you might be interested in a couple of tidbits that fell out:

The next logical step is to set the escape velocity equal to 'c', and then

massage things around and solve for the distance:

2 G M / D = c2

D = 2 G M / c2 We know 'G' and 'c' , so then the distance to the event horizon is

D = (2 x 6.67 x 10-11) M / (3 x 108)2 D = 1.482 x 10-27 M And voyla ! There you have it ... the distance in terms of the mass.

-- For 1 Earth mass, the radius to the event horizon is 8.86 millimeters.

-- For 1 solar mass, it's 2.95 kilometers

-- For 1 million solar masses, it's 2.95 million kilometers, about 7.6 times

the radius of the Moon's orbit, and about 4.2 times the sun's radius.

This helps clarify what's going on with black holes. It's not that they have such

crazy gravity, nor can they reach out and grab you and suck you in as you pass

by. It's just that you can't get CLOSE ENOUGH to the center of mass of any

other kind of body to be in the region of the extreme gravity of an event

horizon.

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Q: Is the event horizon the distance from the singularity at which the acceleration due to gravity exceeds the speed of light?
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