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This depends on whether you consider what is inside the balloon to be a part of the balloon, since the weight of the balloon skin will remain the same regardless of what is inside it. If, however, you consider the contents of the balloon to constitute a part of the balloon's mass then it will always be heavier when inflated, regardless of the density of the substance with which it is inflated. However, in this case the density of the balloon will fall when inflated if the contents are less dense than the material of the balloon, which is highly likely since the substance would probably be a gas. Therefore the balloon would be heavier but less dense.
We are all similar to the experiment the scientist Galileo conducted when testing the laws of gravity. He had been atop the Leaning Tower Of Pisa and had thrown objects of the different weights and they had landed on the ground at the same time. This is because gravity pulls all objects, regardless of mass at the same speed. Some factors which could alter this could be air resistance, which causes friction. So if in a room without air, i think that the balloons will fall at the same time. Normally, though, i think that aside from some circumstances, the smaller balloon will fall first. (if there is air in the big one, of course it won't fall quickly, its mass will be reduced)
The simple answer is the bigger the balloon, the more rubber it will have. However, the actual amount of rubber is determined by its thickness. Thus a large but thin balloon can easily have less rubber than a smaller thicker balloon. Assuming all rubber balloons are made from the same chemical composition, you can determine which has the most rubber simply by weighing them while they are completely deflated. Alternatively, immerse the deflated balloons in water to determine their mass (by the amount of displacement).
depends on the ball you are using!
You could do this by applying pressure to the balloon, you'll notice that as it get's smaller from getting squeezed it becomes harder to compress, because of the higher pressure.
It certainly would be heavier. Air has mass and will add weight.
an inflated because it takes up more room than a deflated one It depends on how you define the basketball. If you define it as just the rubber, then the mass does not change when it is inflated. If you consider the air inside the ball to be part of the ball then adding more air adds more mass. Mass is "stuff". Air has mass because air is stuff.
The gas inside the inflated balloon has mass. At standard atmospheric conditions at sea level air weighs approximately one kilogram per cubic metre. A 10 passenger hot air balloon has an inflated volume of about 9000 cubic metres so the air inside the balloon weighs around nine tonnes!
This depends on whether you consider what is inside the balloon to be a part of the balloon, since the weight of the balloon skin will remain the same regardless of what is inside it. If, however, you consider the contents of the balloon to constitute a part of the balloon's mass then it will always be heavier when inflated, regardless of the density of the substance with which it is inflated. However, in this case the density of the balloon will fall when inflated if the contents are less dense than the material of the balloon, which is highly likely since the substance would probably be a gas. Therefore the balloon would be heavier but less dense.
We are all similar to the experiment the scientist Galileo conducted when testing the laws of gravity. He had been atop the Leaning Tower Of Pisa and had thrown objects of the different weights and they had landed on the ground at the same time. This is because gravity pulls all objects, regardless of mass at the same speed. Some factors which could alter this could be air resistance, which causes friction. So if in a room without air, i think that the balloons will fall at the same time. Normally, though, i think that aside from some circumstances, the smaller balloon will fall first. (if there is air in the big one, of course it won't fall quickly, its mass will be reduced)
The simple answer is the bigger the balloon, the more rubber it will have. However, the actual amount of rubber is determined by its thickness. Thus a large but thin balloon can easily have less rubber than a smaller thicker balloon. Assuming all rubber balloons are made from the same chemical composition, you can determine which has the most rubber simply by weighing them while they are completely deflated. Alternatively, immerse the deflated balloons in water to determine their mass (by the amount of displacement).
Yes, there is more mass in an inflated balloon than a deflated one. The difference is the gas that was used to inflate the balloon. The gas may not weigh very much, but it does make a difference.
depends on the ball you are using!
You could do this by applying pressure to the balloon, you'll notice that as it get's smaller from getting squeezed it becomes harder to compress, because of the higher pressure.
You could do this by applying pressure to the balloon, you'll notice that as it get's smaller from getting squeezed it becomes harder to compress, because of the higher pressure.
If the smaller mass is more dense, like a spoon lifting an inflated balloon. Or if the smaller mass has more electromagnetic properties then the larger one, like a small magnet being able to lift a pile of nails.
the mass of the balloon increases because the size of the balloon has increased. :)