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PV=nRT

if you are fixing PV and T then the question really is how many moles of Helium is 16 g. Take that number of moles and multiply by the molecular weight of Nitrogen (28.02 g/mol) to get the number of grams of N2 needed.

16 g/4.00g per mol = 4 mol He X 28.02 g/mol = x g of N2 needed.

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Q: It takes point 16 g of helium He to fill a balloon How many grams of nitrogen N2 would be required to fill the balloon to the same pressure volume and temperature?
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