0
What else can I help you with?
Can you calculate the number of moles of magnesium used grams permol?
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
What i the mlar mass of magnesium cyanide write the formula?
The formula for magnesium cyanide is Mg(CN)2. To find the molar mass, you would add the molar mass of one magnesium atom (24.305 g/mol), and two cyanide ions (26.02 g/mol each). Therefore, the molar mass of magnesium cyanide is 76.345 g/mol.
How many moles of magnesium are in a sample of 56.4 of magnesium?
To determine how many moles of magnesium are in a sample of 56.4 g, you would first calculate the molar mass of magnesium (about 24.3 g/mol). Then, divide the mass of the sample by the molar mass to obtain the number of moles present (around 2.32 moles in this case).
What are the decomposition of sodium bicarbonate stoichiometry lab answers?
In a sodium bicarbonate decomposition stoichiometry lab, the answers would involve determining the balanced chemical equation for the reaction, calculating the theoretical yield of the products, and comparing it to the actual yield obtained in the experiment. The stoichiometry calculations would involve using the molar ratios of the reactants and products to determine the amounts of substances involved in the reaction.
Magnesium reacts with hydrochloric acid HCl to form magnesium chloride and hydrogen gas. The reaction is Mg plus 2HCl and rarr MgCl2 plus H2 What is the mass of HCl that would be required to completel?
The reaction is balanced, so the mole ratio of Mg to HCl is 1:2. Calculate the molar mass of HCl (1 mol HCl = 1g + 1g = 36.5g), then use stoichiometry to convert the mass of Mg to moles of HCl. Finally, divide the mass of Mg by 1 (from the ratio 1:2) and multiply by the molar mass of HCl to find the mass needed.
Can you calculate the number of moles of magnesium used grams permol?
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
What i the mlar mass of magnesium cyanide write the formula?
The formula for magnesium cyanide is Mg(CN)2. To find the molar mass, you would add the molar mass of one magnesium atom (24.305 g/mol), and two cyanide ions (26.02 g/mol each). Therefore, the molar mass of magnesium cyanide is 76.345 g/mol.
How many moles of magnesium are in a sample of 56.4 of magnesium?
To determine how many moles of magnesium are in a sample of 56.4 g, you would first calculate the molar mass of magnesium (about 24.3 g/mol). Then, divide the mass of the sample by the molar mass to obtain the number of moles present (around 2.32 moles in this case).
How much sodium hydroxide in grams must be added to seawater to completely precipitate 86.9mg of magnesium?
To completely precipitate 86.9mg of magnesium from seawater, you would need to add an equal molar amount of sodium hydroxide. The molar mass of magnesium is about 24.3 g/mol, so 86.9mg is equivalent to about 3.57 mmol of magnesium. You would need the same amount of mmol of sodium hydroxide to completely precipitate the magnesium.
What are the decomposition of sodium bicarbonate stoichiometry lab answers?
In a sodium bicarbonate decomposition stoichiometry lab, the answers would involve determining the balanced chemical equation for the reaction, calculating the theoretical yield of the products, and comparing it to the actual yield obtained in the experiment. The stoichiometry calculations would involve using the molar ratios of the reactants and products to determine the amounts of substances involved in the reaction.
What is the number of magnesium atoms that equal a mass of 24.31?
24.31 grams of magnesium is one mole of magnesium, so that is 6.022 X 1023 atoms of magnesium.
How many grams of magnessium chloride are in 1liter solution 2.5M?
Magnesium chloride has a molecular weight of 95.2, so 1 litre of 1 molar MgCl2 would have 95.2g. A 2.5 molar solution would have 2.5X95.2g per litre = 238grams
What weight of magnesium would react with 9.125g of hydrochloric acid?
To find the weight of magnesium needed to react with 9.125g of hydrochloric acid, you would first balance the chemical equation between magnesium and hydrochloric acid. Then, calculate the molar ratio between magnesium and hydrochloric acid. Finally, use the molar mass of magnesium to determine the weight needed for the reaction.
Magnesium reacts with hydrochloric acid HCl to form magnesium chloride and hydrogen gas. The reaction is Mg plus 2HCl and rarr MgCl2 plus H2 What is the mass of HCl that would be required to completel?
The reaction is balanced, so the mole ratio of Mg to HCl is 1:2. Calculate the molar mass of HCl (1 mol HCl = 1g + 1g = 36.5g), then use stoichiometry to convert the mass of Mg to moles of HCl. Finally, divide the mass of Mg by 1 (from the ratio 1:2) and multiply by the molar mass of HCl to find the mass needed.
How would the formula of the oxide be influence if impure magnesium was used?
The formula of the magnesium oxide formed would not change at all if impure magnesium was used, but less of the magnesium oxide would be formed than if the same amount of pure magnesium had been used. Depending on the chemical nature of the impurities, other products might be formed, or the impurity might simply remain as a contaminant of the magnesium oxide.
Why is the formula for magnesium sulfide MgS?
Magnesium sulfide forms when magnesium (Mg) with a +2 oxidation state reacts with sulfur (S) in a 1:1 ratio to achieve a stable octet configuration. The chemical formula MgS reflects this stoichiometry ratio of the elements in the compound.
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
