None. CH4 is methane. NH3 is ammonia. You have made some kind of error.
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
No. Methane is CH4 whereas ammonia is NH3.
You would multiply the number of grams x Avogadro's number=number of molecules: (21.6g) X (6.022x10^23)= 1.301x10^25 molecules
nh3-nh3 because they are both polar molecules
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
Water: H2O Ammonia: NH3 Methane: CH4
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
No. Methane is CH4 whereas ammonia is NH3.
You would multiply the number of grams x Avogadro's number=number of molecules: (21.6g) X (6.022x10^23)= 1.301x10^25 molecules
nh3-nh3 because they are both polar molecules
How many molecules are in 30 liters of methane (CH4) at STP
To find moles, simply divide the number of representative particles (in this case, molecules of methane) by Avogadro's number (6.02x1023.)2.45x1023/6.02x1023 = approx. 0.41 moles (the exponents cancel out.)
First divide 1 by molecular mass 16.then multiply by Avagadro number
Water is H2O, ammonia is NH3, carbon dioxide is CO2 and methane is CH4.
No. Ammonia is NH3 gasMethane is CH4 gasthey are different in most ways other than the fact that they are both gases.
The periodic table lists only elements and not compounds / molecules like CH4.