The formula of magnesium carbonate is MgCO3. It therefore has one atom each of magnesium and carbon and 3 atoms of oxygen. The gram molecular weight is therefore
24.305 + 12.011 + 3(15.999) = 84.313. This answer to the problem is twice this value, 168.626 grams, if the number "two" is considered to be exact.
For this you need the atomic (molecular) mass of MgCl2. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. MgCl2= 95.3 grams
2.00 moles MgCl2 × (95.3 grams) = 190.6 grams MgCl2
Molar mass 95.211x 7.08= 743g (Rounded with sig figs)
70.90 g
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
Yes
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
24.305 grams/mole Magnesium X 5 moles = 121.525 grams. The correct number of significant digits depends on the values given in the question. Since there was only one value (5), and it refers to a perfect integer amount (5 moles). The question of the correct number of significant digits is undefined and depends entirely on the number of significant digits available for the Atomic Mass of Magnesium. Since there are 5 significant digits in the Atomic mass used, the answer would be correctly stated as 121.53 grams to 5 significant digits.
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
262.5
Yes
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
1,11 moles of magnesium have 26,97855 g.
23.3772 grams are there in four tenths moles of sodium chloride
There are 0.13 moles in 20 grams of magnesium nitrate.
24.305 grams/mole Magnesium X 5 moles = 121.525 grams. The correct number of significant digits depends on the values given in the question. Since there was only one value (5), and it refers to a perfect integer amount (5 moles). The question of the correct number of significant digits is undefined and depends entirely on the number of significant digits available for the Atomic Mass of Magnesium. Since there are 5 significant digits in the Atomic mass used, the answer would be correctly stated as 121.53 grams to 5 significant digits.
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
88,1 moles of magnesium is equivalent to 2 141,27 g.
.73 moles