262.5
The solute is the material you're dissolving into your solution; in this case the ammonium chloride. 0.341 M (molar) means you need 0.341 mol/L.500mL = 0.5L, so to make 500 mL of solution you actually need 0.5*0.341 = 0.1705 moles of ammonium chloride.ammonium chloride weighs 53.491 g/mol (14.0067+1.00794+35.453, all the molecular weights of the elements in NH4Cl)0.1705*53.491 = 9.12 grams
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
To find the number of chloride atoms in 654.5 grams of calcium chloride, you would first calculate the number of moles of calcium chloride using its molar mass. Then, since each formula unit of calcium chloride contains two chloride ions, you would multiply the number of moles by 2 to find the number of chloride atoms.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol. Therefore, 4.40 moles of NaCl would be equal to 257.14 grams.
Jessica should bring about 23.6 grams of sodium chloride (NaCl) to the laboratory, as 1 mole of NaCl weighs 58.5 grams. This is calculated by multiplying the number of moles by the molar mass of NaCl (0.40 moles * 58.5 grams/mole = 23.6 grams).
To find the number of grams of ammonium chloride in 0.500L of a 2.00M solution, we need to use the formula: concentration (M) = moles of solute / volume of solution (L). First, calculate the moles of ammonium chloride present in 0.500L of the solution using C = n/V. Then, convert moles to grams by multiplying by the molar mass of ammonium chloride (NH4Cl).
The molar mass of ammonium chloride (NH4Cl) is approximately 53.49 g/mol. To find the number of grams in a certain quantity, you would need to know the number of moles present using the formula: mass (g) = number of moles * molar mass.
The number of moles is 18.56.
The solute is the material you're dissolving into your solution; in this case the ammonium chloride. 0.341 M (molar) means you need 0.341 mol/L.500mL = 0.5L, so to make 500 mL of solution you actually need 0.5*0.341 = 0.1705 moles of ammonium chloride.ammonium chloride weighs 53.491 g/mol (14.0067+1.00794+35.453, all the molecular weights of the elements in NH4Cl)0.1705*53.491 = 9.12 grams
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
To find the number of chloride atoms in 654.5 grams of calcium chloride, you would first calculate the number of moles of calcium chloride using its molar mass. Then, since each formula unit of calcium chloride contains two chloride ions, you would multiply the number of moles by 2 to find the number of chloride atoms.
23.3772 grams are there in four tenths moles of sodium chloride
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol. Therefore, 4.40 moles of NaCl would be equal to 257.14 grams.
To determine the number of moles of ammonium ions in 8.738 g of ammonium carbonate, first calculate the molar mass of ammonium carbonate (NH4)2CO3. Then, divide the given mass by the molar mass to find the number of moles. Since there are two ammonium ions in one formula unit of ammonium carbonate, multiply the number of moles by 2 to get the moles of ammonium ions.
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
assuming that 8.778 is in grams then there are 0.1069 moles in 8.778 grams of ammonium carbonate here is the math:(NH4)2CO3 N2=14.01g H8=8.08g C=12.01g O3=48.00 14.01+8.08+12.01+48.00=82.10g/mole 8.778g X 1 mole/82.10g=0.1069moles