So molarity is moles in every litre. To get 5 litres down to 1 you have to divide. what you do to litres you have to do to moles. i.e. 5/5 is 1 molar.
Molarity = moles of solute/Liters of solution Get moles of Fe2O3 160.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams) = 1.0 mole Molarity = 1.0 mole/1.0 liters = 1.0 M Fe2O3
237.5 mL (200mL if you are keeping track of significant figures). Molarity is moles/liters. To make 900mL of a 2M solution, you need 1.8 moles of solute. There are 1.8 moles of solute in 237.5 mL of 8M solution.
Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )
molarity of moles of solute/liters of solution(not solvent) the volume of the solvent(even if it started at 1 L) would change after adding the solute depending on the molar mass, density, etc of the solute, the molarity would be different
Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
Molarity (M) = mole of solute (mol)/volume of solution that it is dissolved into (L) Make sure that the volume is converted to L if it isn't already, otherwise you will get wrong answers.
Molarity=moles of solute/liters of solvent=5mol/10L=0.5M
Because you have 6.68 moles of Li2SO4 and 2.500 liters of water, the overall molarity of your solution is 2.67 M.
molarity is #moles divide by # liters, so 3.0 divided by 0.500 is 6.0 molarity (2 siginficant figures is all you are allowed)
Molarity is moles per litre. So you have to convert volume to a litre. i.e. 0.5x2 is a litre. so you have to do the same to moles. 5x2 is 10 moles. as this is per litre, it is a 10 molar solution.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
Molarity = moles of solute/Liters of solution Get moles of Fe2O3 160.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams) = 1.0 mole Molarity = 1.0 mole/1.0 liters = 1.0 M Fe2O3
237.5 mL (200mL if you are keeping track of significant figures). Molarity is moles/liters. To make 900mL of a 2M solution, you need 1.8 moles of solute. There are 1.8 moles of solute in 237.5 mL of 8M solution.
186g C6H12O6 Use a concentration formula. Molarity - moles of solute/liters of solution. molarity = 1 moles of solute= x liters= 1 solve the equation and x= 1. One mole of glucose is equal to 186 grams.