-2 for each O
+6 for S
-2 for each O +6 for S
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
-2 for each O, +6 for S
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
+6 oxidation state
+4
-2 for each O +6 for S
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
-2 for each O, +6 for S
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
+6 oxidation state
The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states
SO3 is the sulfate radical; it contains sulfur and oxygen.
S is +6, O is -2
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
The are two elements in SO3: sulfur and oxygen.