-2 for each O
+6 for S
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
-2 for each O +6 for S
-2 for each O, +6 for S
+6 oxidation state
S is +6, O is -2
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
-2 for each O +6 for S
-2 for each O, +6 for S
+6 oxidation state
The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states
+4
S is +6, O is -2
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
Likely it is; Magnesium sulfite Mg(2+) and SO3(2-) but SO3 can also be sulfur trioxide which also has an oxidation number of 2- then; Magnesium trioxide would be the name, but this is much less likely
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
The oxidation state of an individual sulfur atom in (SO3)2- is 4.