If you think to magnesium oxide and to concentration of oxygen in MgO the answer is 40,007 33 % oxygen.
The molar mass of MgO is 40.3 g/mol (Mg: 24.3 g/mol, O: 16 g/mol). The molar mass contribution of oxygen in MgO is 16 g/mol. Therefore, the percent composition of oxygen in MgO is (16 g/mol / 40.3 g/mol) * 100 = 39.7%.
The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
The empirical formula of this compound would be MgO.
No. MgO is magnesium oxide. It is a compound. Compounds cannot be considered as metals or nonmetals.
The chemical formula for magnesium oxide is MgO, where Mg represents magnesium and O represents oxygen.
The percent of Mg calculated will be too high. Let's say that you reacted 1.00 g of Mg and made some MgO, but so much MgO escaped as smoke that only 1.00 g of MgO was left. You would then conclude from the numbers that the mass of O in the MgO was zero! This would lead you to conclude that the percent of Mg in the MgO was 100 %, which is silly and clearly in error. Although this is an extreme example, it illustrates that the loss of MgO as smoke from the crucible leads to a percent of Mg (calculated) that is above the expected 60.3 %.
The molar mass of MgO is 40.3 g/mol (Mg: 24.3 g/mol, O: 16 g/mol). The molar mass contribution of oxygen in MgO is 16 g/mol. Therefore, the percent composition of oxygen in MgO is (16 g/mol / 40.3 g/mol) * 100 = 39.7%.
The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
The empirical formula of this compound would be MgO.
60%
Magnesium nitride (Mg3N2) has a higher percentage composition of magnesium than magnesium oxide (MgO) does. The percentage composition of magnesium in magnesium nitride is 72.2% and the percentage composition of magnesium in magnesium oxide is 60.3%.
the Lewis formula for MgO is Mg2+[O]2- Which mean Mg loses 2 electrons and O gains 2 electrons to be stable.
Pure MgO will absorbe water from the air causing an error in the experiment if that extra mass is not accounted for. By adding water in the very beginning you eliminate this error.
No. MgO is magnesium oxide. It is a compound. Compounds cannot be considered as metals or nonmetals.
Mg + O ----> MgO
The chemical formula for magnesium oxide is MgO, where Mg represents magnesium and O represents oxygen.
To determine the number of moles in 106 grams of MgO, you need to divide the given mass by the molar mass of MgO. The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg + 16 g/mol for O). Thus, 106 g / 40.3 g/mol = approximately 2.63 moles of MgO.