Depends on how accurate you need to be.
Ideally 56.11g of KOH made up to 1L.
Dissolve 56.11g in say 500ml then make up to 1l using water - 1l volumetric is the way to go.
If you need 1000L then I would suggest 56.11kg chucked into 1000L
All the best
First, you will need about 5.7g of KOH. Then you will dissolve the KOH solution in 1dm of water.
18 grams of KOH add 10 ml of water dilut with methanol to 500 ml. allow to stand for 24 hours
14.5 g in to 500 mL flask
No because the two substances are different.
What volume(L) of 3M KOH solution can be perpared by diluting 0.5 L of %M KOH solution?
ethanolic KOH can precipitate the impurities in solution
Take 5.7g of KOH and dissolve in 1dm of water
Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH
No because the two substances are different.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
What volume(L) of 3M KOH solution can be perpared by diluting 0.5 L of %M KOH solution?
because KOH is hygroscopic
A solution of NaCl 1 M.
1% solution of KOH contains 1g of KOH in 100g of solution. This means that you need to mix 1g of KOH and 99g of water.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
KOH is the reactant in this reaction:2 MnO2 + 4 KOH + O2 = 2 K2MnO4 + 2 H2O
The answer is 12,831 g KOH.
ethanolic KOH can precipitate the impurities in solution
The answer is10,436 g.