Preparation of 1M KOH solution?
Wiki User
April 17, 2013 5:34PM
Depends on how accurate you need to be.
Ideally 56.11g of KOH made up to 1L.
Dissolve 56.11g in say 500ml then make up to 1l using water - 1l volumetric is the way to go.
If you need 1000L then I would suggest 56.11kg chucked into 1000L
All the best
Related Questions
14.5 g in to 500 mL flask
The pH value of a solution depends on its concentration and the temperature. For example, at 298 K, a 1M solution of KOH has a pH value of 13.
No because the two substances are different.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
What volume(L) of 3M KOH solution can be perpared by diluting 0.5 L of %M KOH solution?
First, you will need about 5.7g of KOH. Then you will dissolve the KOH solution in 1dm of water.
It is a strongly alkaline solution of KOH, i.e. KOH dissolved in water.
This solution - 750 mL of 5 M KOH - contain 3,75 moles of KOH.
because KOH is hygroscopic
No, 1M H2SO4 is equal to 2N H2SO4.
1% solution of KOH contains 1g of KOH in 100g of solution. This means that you need to mix 1g of KOH and 99g of water.
Molarity=Moles of solute/Liters of solution 1.350 g KOH = 0.02406 mol KOH 0.02406 mol/0.2500 L =0.09624 M of KOH
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
1M solution has higher concentration than 1m solution
ethanolic KOH can precipitate the impurities in solution
KOH is the reactant in this reaction: 2 MnO2 + 4 KOH + O2 = 2 K2MnO4 + 2 H2O
The answer is 12,831 g KOH.
35,0 mL of a 5,50 M KOH solution contain 10,8 g KOH.
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
Molarity = moles of solute/Liters of solution 1.5 M KOH = 3.0 moles KOH/Liters Liters = 3.0 moles KOH/1.5 M KOH = 2 liters or = 2000 milliliters
Molarity = moles of solute/Liters of solution 1.5 M KOH = 3.0 moles KOH/volume = 2.0 Liters
Take 5.7g of KOH and dissolve in 1dm of water
The answer is10,436 g.