Q, m, c, and T are symbols commonly used in physics and thermodynamics:
To find the grams of water, we first need to calculate the change in temperature of the water using the specific heat capacity of water (4.18 J/g°C). Delta T = Q / (m * C), where Q is the heat supplied (348 J), C is the specific heat capacity of water (4.18 J/g°C), and m is the mass of water in grams. Rearranging the formula to solve for mass, we get m = Q / (C * delta T). Plugging in the values, we find m = 348 / (4.18 * 5.2) ≈ 16.7 grams of water.
Using the formula q = mcΔT, where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature, we can calculate the specific heat of the metal. Plugging in the given values, we have 124.2 J = (18.0 g) * c * (40°C - 25°C). Solving for c gives us a specific heat of approximately 0.46 J/g°C for the unknown metal.
The heat released can be calculated using the formula: Q = m * c * ΔT, where Q is the heat released, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Converting the units, the heat released is approximately 2.44 kJ.
The specific heat capacity of glass can be calculated using the formula q = m * C * ∆T, where q is the heat absorbed (32 J), m is the mass (4.0 g), C is the specific heat capacity, and ∆T is the change in temperature (40 K). Rearranging the formula to solve for C gives C = q / (m * ∆T), which equals 0.2 J/gK for the specific heat capacity of this glass.
The specific heat can be calculated using the formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat, and ΔT is the temperature change. Plugging in the values, we get 2000 J = 4g * c * 5°C. Solving for c gives a specific heat of 100 J/g°C.
The specific heat (c) can be calculated by rearranging the equation as c = Q / (m x T), where Q is the heat energy transferred, m is the mass of the substance, and T is the temperature change.
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In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.
h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = H k Q 7 _ o W q K p c
That equation is, q(Joules) = mass * specific heat ( symbol is C ) * (delta, a triangle) change in temperature That is to say delta means, Temperature Final - Temperature Initial q is a constant and not subject to change as temperature is
The equation for thermal energy is Q = mcΔT, where Q is the thermal energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
The formula to find the specific heat of water ( Q ) is: ( Q = mc\Delta T ), where (m) is the mass of the water, (c) is the specific heat capacity of water, and ( \Delta T ) is the change in temperature of the water.
The formula to find thermal energy is: Q = mc∆T, where Q is the thermal energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ∆T is the change in temperature.
To find the grams of water, we first need to calculate the change in temperature of the water using the specific heat capacity of water (4.18 J/g°C). Delta T = Q / (m * C), where Q is the heat supplied (348 J), C is the specific heat capacity of water (4.18 J/g°C), and m is the mass of water in grams. Rearranging the formula to solve for mass, we get m = Q / (C * delta T). Plugging in the values, we find m = 348 / (4.18 * 5.2) ≈ 16.7 grams of water.
You have to know mass in grams, energy (q) gained or lost in Joules, and change in temperature,ΔT, in degrees C. ΔT = Final temp - initial temp. The specific heat = q/(m)(ΔT) = J/g•oC
Q=cm(delta)T "Q" is the heat "C" is the specific heat "m" is the mass "(delta)T" is the change in temperature * just plug in what you have and then solve for what you don't have...and thats how you find the specific heat of a substance.
M. T. C. Cronin was born in 1963.