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say your mass (m) is 100 kg

velocity (v) at equator = 40 030 000 / 86164 = 464.6 metres / sec

earth radius(r) = 6 371 000 metres

acceleration due to gravity at earths surface (g) = 9.82 (m/s)/s

.

gravity force at earth surface ( f = m * g) = 100 * 9.82 = 982 newtons

.

centripetal force at equator f = m * ((v^2)/r)

f = 100 * ((464.6^2)/6 371 000)

f = 3.39 newtons

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Q: Standing at the equator What is the centripetal force you experience due to the rotation of the earth How much does this force compare to the gravitational force you experience would it be noticeabl?
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