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In a series circuit, all the current passes through the one circuit. Any break will totally remove power from all of the circuit.Parallel circuits have more than one branch where the current can flow. A broken wire will only affect one part, the rest of the circuit will still pass current.In a series circuit, all the current passes through the one circuit. Any break will totally remove power from all of the circuit.Parallel circuits have more than one branch where the current can flow. A broken wire will only affect one part, the rest of the circuit will still pass current.
All the bulbs will go out. In a series circuit, the current at all points is the same. This is Kirchoff's Current Law. If you loosen or remove a bulb in a series circuit, the current at that bulb becomes zero, and by Kirchoff's Current Law, the current in every part of the circuit also becomes zero.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
if we remove a resistor from the parallel connection the effective resistance value will be increased.
the reason one needs to remove metal from one's hands(including fingers or wrist area) is that a circuit can be made if the metal comes in contact with the circuit parts. if this happens, a circuit could be made through the jewelry and the jewelry would then be carrying voltage and/or current which of course, would be attached to the person wearing it! This would be a short circuit causing damage to the circuit, and also to the person wearing the jewelry...so watch out!
In a series circuit, all the current passes through the one circuit. Any break will totally remove power from all of the circuit.Parallel circuits have more than one branch where the current can flow. A broken wire will only affect one part, the rest of the circuit will still pass current.In a series circuit, all the current passes through the one circuit. Any break will totally remove power from all of the circuit.Parallel circuits have more than one branch where the current can flow. A broken wire will only affect one part, the rest of the circuit will still pass current.
The battery is the power source of the circuit. It supplies current to the circuit and the circuit is simply a path for the current to follow. When you remove the current (battery), the path still exists but there is no current going through it.
Over load in circuit? Remove starter and have it checked at auto parts for excessive current draw Dead short to ground in circuit? Over load in circuit? Remove starter and have it checked at auto parts for excessive current draw Dead short to ground in circuit?
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All the bulbs will go out. In a series circuit, the current at all points is the same. This is Kirchoff's Current Law. If you loosen or remove a bulb in a series circuit, the current at that bulb becomes zero, and by Kirchoff's Current Law, the current in every part of the circuit also becomes zero.
Removing any bulb breaks the continuity of a series circuit, stopping the flow of electrical current. Removing a bulb in a parallel circuit does not interrupt the current flow, so the remaining lights continue to conduct electrical current.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
if we remove a resistor from the parallel connection the effective resistance value will be increased.
The brightness of the lights may or may not change depending on the circuit in which they are wired. In a series circuit, all the bulbs (called lamps) will experience the same current flow. The same amount of current will be flowing through each one, and each one will be dropping some amount of voltage. If we remove some of the lamps and reconnect the circuit, the lamps will glow brighter because there is less total resistance in the circuit. The remaining lamps will end up dropping more voltage, and will glow brighter. In a parallel circuit, removing bulbs (or adding them) will not affect the operation of the other lamps in the circuit (providing the voltage source is adequate). We know that each of the lights in a household circuit is wired in parallel, and turning one or more on or off won't affect the operation (the brightness) of any other light that is on.
First,remove all current and voltage sources ie replace voltage source with a short and keep current source open.Now draw the equivalent resistance-only circuit and find the equivalent resistance as viewed from the terminals of the circuit.
An 'overcurrent' can be an 'overload current' or a 'short-circuit current'. An overload current exists when the load connected to a circuit draws more current than the circuit is designed to carry continuously. A short-circuit current is a high current resulting from a fault between a line conductor and the neutral conductor or earth.
You have to replace the wire (as you are increasing the current capacity), the outlet, and the breaker. Essentially you have to remove the old circuit and put in a new one. You can't reuse parts of the old circuit as you are increasing the current capacity and they would be underrated.