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More the number of shells in an atom, more away will be the electrons from the nucleus. Hence, weaker will be the attraction between nucleus and outermost electrons. So atom with more shells will let go their electrons easier than atoms with fewer shells.
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Beryllium (Be) has a greater shielding effect than magnesium (Mg) because it has fewer electron shells. In Be, the single electron in its outer shell experiences less shielding from the inner electrons, while in Mg, the additional electron shells introduce more inner electrons that can shield the outer electrons more effectively. Therefore, the overall shielding effect is greater in Mg due to its larger number of electron shells.
Lithium (Li) has a higher shielding effect compared to beryllium (Be). This is because Li has fewer protons in its nucleus than Be, leading to a weaker effective nuclear charge experienced by the outermost electrons. As a result, the inner electrons in Li can shield the outer electrons more effectively. Consequently, the shielding effect is generally stronger in elements with fewer protons when comparing atoms in the same group.
Atoms increase their electronegativity by enhancing their ability to attract electrons in a chemical bond. This typically occurs as the atomic number increases, resulting in a greater positive charge in the nucleus that can pull electrons closer. Additionally, atoms with fewer electron shells can exhibit higher electronegativity due to reduced electron shielding, allowing the nucleus to exert a stronger pull on bonding electrons. Elements such as fluorine and oxygen showcase this trend, as they have high electronegativities due to their effective nuclear charge and electron configuration.
The atomic radius of sulfur is larger than that of chlorine because sulfur has more electron shells, leading to a greater distance between the nucleus and the outermost electrons. Chlorine has a smaller atomic radius due to its fewer electron shells.
It seems there's a typo in your question, as it compares lithium (Li) to itself. If you meant to compare lithium (Li) with another element, such as sodium (Na), lithium is smaller due to its higher effective nuclear charge and fewer electron shells, resulting in a stronger attraction between the nucleus and its electrons. This leads to a smaller atomic radius compared to larger elements with more electron shells, which experience greater electron shielding.
C.their atomic radius is small D.layers of electron shells shield the protons' attractive force fewer layers of electron shells create less shielding of the protons' attractive force
Valency is the number of electrons in the outer shell the charge is how many electrons is needed to form an octet (full valence = 8 electrons) Eg. Sulfur valence = 6 charge = -2 (needs to gain 2 electrons to gain an octet)
High ionization energy is primarily caused by a strong effective nuclear charge, which occurs when there are many protons in the nucleus attracting electrons more strongly. Additionally, a smaller atomic radius leads to electrons being closer to the nucleus, increasing the energy required to remove them. Electrons in a stable, filled subshell configuration also contribute to higher ionization energies, as they are more tightly bound. Lastly, increased electron shielding by inner electrons can reduce ionization energy, making elements with fewer inner electrons more likely to exhibit high ionization energies.
The electrons in the 2p subshell have more energy than those in the 2s subshell, that is energy per electron.See Wikipedia 'Electron Shells' for more on this subject.