Load!
at lower power factor current drawn by load is high and at higher pf the current drawn is less...
maximum demand is measured in kva because current drawn is dependent on power factor for the same load and current drawn is calculated with kva
The current flowing through a transformer's secondary is the current drawn by the load, so it will be exactly the same as the current flowing through your induction motor -assuming that is the load. Don't really understand the point of your question!
The 7805 is a standard 5 volt regulator with a voltage input, a regulated 5V output and an earth reference. With no load on the 5V output, the current drawn by the regulator is nor more than a few milliamps. The actual figure varies from one type to another. Once a load is added to the 5V output, the current drawn from the battery is the same as the current drawn by the load itself (plus the few milliamps drawn by the regulator itself). As an example, if the load current is measured at 1 amp, then the current drawn from the battery will also be 1 amp. If current draw is a problem, then consider a switching regulator instead of a linear type. Switching regulators will be more efficient and for a 1 amp load, it is possible to see only a 0.6 - 0.7A current from the battery itself. as well as conserving battery life, the regulator will also generate less heat than the 7805.
You need to divide the supply voltage by the impedance of the load. The impedance of the load is the vectorial sum of its resistance and reactance, where reactance is proportional to frequency.
load
It is a the current drawn by the application that is connected to the power source
at lower power factor current drawn by load is high and at higher pf the current drawn is less...
Load current is simply the name given to the current drawn by a load from its supply. In the case of a d.c. circuit, this is determined by dividing the supply voltage by the resistance of the load; in the case of an a.c. circuit, it is determined by dividing the supply voltage by the impedance of the load.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
maximum demand is measured in kva because current drawn is dependent on power factor for the same load and current drawn is calculated with kva
The circuit is designed so that at maximum load current the shunt regulator draws virtually no current and at minimum load current, the shunt voltage regulator passes the full current. As a result, it can be seen that shunt regulators are inefficient because maximum current is drawn from the source regardless of the load current, i.e. even when there is no load current.
If your question is, "Can a capacitor bank reduce high loads in electrical systems?" Not really. In an AC system, a capacitor bank can be used to balance the complex power drawn by the load. If done correctly, this can reduce the current being drawn by the load. If done incorrectly, this can increase the current being drawn by the load. Look up "power factor correction" for more details.
The current flowing through a transformer's secondary is the current drawn by the load, so it will be exactly the same as the current flowing through your induction motor -assuming that is the load. Don't really understand the point of your question!
Different things are measured different ways according to their properties.The current drawn from a supply is aften called the load current, but the actual load is the device which is connected to a supply and through which the current flows.
With varying power factor the load current drawn changes, which in turn affects the voltage regulation
The voltage drop during starting a load specially motor load is due to absence of back emf and due to high starting current drawn. In case of resistor/heaters, they are also wound like coil so they will also have some inductance and hence during starting, due to absence of back emf, a high current is drawn and hence the voltage drop. While stopping the load current drawn is smaller than the starting current. In the cases of motors and transformers their starting current is about 6 - 8 times the full load current and hence the above phenomenon asked in the question is observed.