it depends on the type of the circuit you are analyzing..it could be a voltage divider, emitter follower, be specific on what type of circuit and maybe i can help you aobut this question.
A MOSFET (metal oxide semiconductor field effect transistor) can be used INSTEAD of a BJT (bypolar junction transistor, so transistor is redundant in your question), if the circuit in question is modified to allow it and the MOSFET is chosen appropriately. BJT's will usually have a higher intrinsic gain, but have lower input resistance. Also a BJT in general will work better at higher frequencies than a MOSFET (unless you choose a high frequency MOSFET) due to the capacitive nature of MOSFETs.
Yes. Input DC voltage would be root2 times the input AC voltage.
It does have armature resistance.
The typical ohmmeter measures DC resistance by providing DC current and measuring the voltage drop accross the resistor. By definition, the 'ideal' capacitor is an open circuit to DC current and voltage. By definition, an open circuit has infinite resistance. Of course, real-world capacitors are not ideal. They have a very high parallel leakage resistance and a very small series resistance. And, different meters can measure different ranges of resistance. So, you may not get an infinite/overload measurement on some capacitors with some meters. You may get a very high resistance instead. If so, you are not really measuring the resistance of the 'capacitor', but rather that of the imperfections in the component manufactured to be a capacitor. ANSWER: The ohmmeter battery will charge the capacitor in 5 time RC after that it quirts there is no more current flow. Any body that claim to be able to check resistance of a capacitor i just a wannabe
You can measure high voltage by using Potential Transformer (PT). or by using utility meter or power manager. ANSWER: Adding a hi resistance in series with a low resistance and measuring that voltage drop. If the resistance is known then current is determined and the source can be calculated. transformers do not work well with DC,
MOSFET has high input impedance and offer input signal isolation from the circuit
A MOSFET (metal oxide semiconductor field effect transistor) can be used INSTEAD of a BJT (bypolar junction transistor, so transistor is redundant in your question), if the circuit in question is modified to allow it and the MOSFET is chosen appropriately. BJT's will usually have a higher intrinsic gain, but have lower input resistance. Also a BJT in general will work better at higher frequencies than a MOSFET (unless you choose a high frequency MOSFET) due to the capacitive nature of MOSFETs.
Class E resonant inverter transform energy from input DC to AC. They work on the basis of resonance and reset the transformer core through resonant reset technique. They usually perform zero voltage switching by turning ON the MOSFET when the MOSFET drain-source voltage is zero.
output resistance decreases and input resistance increases
it can exchange the current is much larger and has Avery low resistance when it is turned on.the mosfet is not removed from the circuit when the supply is on because it flow the high current.
Because of its much higher input impedance. When measuring voltage, that makes the voltmeter appear to the circuit as if it's not there, so the presence of the voltmeter doesn't change the operation of the circuit.
A: a transformer input will always demand an AC input a DC input may actually damage it if enough power is available
The resistance needed is1/(the current flowing through the resistance) ohms.
Use a mosfet driver instead of a simple resistor. Using a resistor to control the mosfet is a bad idea anyways because you will have terrible control (mosfets are voltage controlled. Take a look at the response curve for your mosfet). If your mosfet is fully on, its ratings may be too low for continuous operation or the power dissipation is too low for the transition between off an on an that is killing your mosfet.
12v dc to 3v dc
DC can stand for "direct current" which is what you get from a battery. dc-in would be a connection for DC input.
Yes. Input DC voltage would be root2 times the input AC voltage.