The resistance needed is
1/(the current flowing through the resistance) ohms.
7K ohm
12v dc to 3v dc
It is equal to: 20v^2 +4v -24
Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
V + 47 - 5V = 287 gather V's together 47 - 4V = 287 subtract 47 from both sides 47 - 47 - 4V = 287 - 47 - 4V = 240 divide both sides integers by - 4 (- 4/ - 4)V = 240/- 4 V = - 60 -----------------check in original equation ( - 60 ) + 47 - 5( - 60) = 287 - 13 + 300 = 287 287 = 287 ----------------checks
assuming 5v steady the 2 amps can be virtual zero by reducing the load present
There are actually three pieces to this puzzle - resistance. And you're missing that one.
Most Accurate Answer:The cooling fan.This can sometimes be misinterpreted as the CPU fan, but that is the HEAT SINK that is located on top of the central processing unit on the motherboard.The cooling fan is on the case, next to the power supply to prevent overheating and to keep the case cool (sometimes referred to as the CASE FAN).---------------------------------------------------------------------------------------------------------------------------------------SUBMITTED BY PREVIOUS EDITOR:which are supplied by the P1 power supply connector?a)12v,6v and 3vb)12v,5v and 3.3vc)12v,4v and 1.8vd)6v,5v and 4v
Ohm's Law: Current = voltage divided by resistance. 5 V divided by 12 KΩ is 416 2/3 ma
-5v^2 over 4(t^2)(u^2)
4 multiplyed by a number (Variable) plus 5 multiplyed by a number (V) equals 15 4v + 5v = 15 15/5 = v 15/4 = impossibility >_< Sorry :~) v = ImPoSiBiLiTy
+5v supply is alone needed for Intel 8085 Microprocessor