KClO3 --> KCl + 3O2 is a decomposision or breakdown reaction or reversed oxidation
The chemical formula (not equation) is KClO3
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
chemical change
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
2KClO3 --> 2KCl + 3O2
The chemical formula (not equation) is KClO3
KClO3+3H2SO3=KCl+3H2SO4
This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}
O2 is oxygen molecule; KCl is potassium chloride
This chemical reaction is:2 KClO3 --------------(MnO2)---------------2 KCl + 3 O2
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
Unbalanced Equation: KClO3 ===> KCl + O2 Balanced Equation: 2KClO3 ===> 2KCl + 3O2
This reaction is:2 KClO3 = 3 O2 + 2 KCl
chemical change
Formula: KClO3
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
The name of the compound with the formula KClO3 is "potassium chlorate".