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No, other way around. The energy difference between the higher level and the lower, appears as photon energy.
by applying a voltage across the boundary of two semi-conductors electrons are forces to travel across the boundary. This boundary has a voltage drop and the electrons are required to lose a discrete amount of energy in crossing it. In the case of the light emitting diode, it is a energy in the range of visible light.
No, the most energy efficient bulbs are LED (Light Emitting Diode) light bulbs.
the state of glowing while at a high temperature, caused by electrons in vibration atoms and molecules that are shaken in and out of their stable energy levels, emitting radiant energy in the process. The peak frequency of radiant energy is proportional to the absolute temperature of a heated substance
Yes. When electrons go from a higher energy orbital to a lower one, they release photons (ie: light).
They return to their ground state from an excited state induced by the electric field between the two ends of the light.
the state of glowing while at a high temperature, caused by electrons in vibration atoms and molecules that are shaken in and out of their stable energy levels, emitting radiant energy in the process. The peak frequency of radiant energy is proportional to the absolute temperature of a heated substance
yes. it travels as photons which are individual quantum of light, caused by the electrons losing quanta of energy
It takes energy to get those electrons up out of their orbitals. It is when they "fall back" and return to their orbitals that they release energy. The energy released will be electromagnetic energy, and if the energy is high enough (but not too high), it will appear as visible light. This is what is happening in a fluorescent tube when it is turned on and emitting light.
the sun loses nergy by emitting light duhhhh breanna Katrice smith
No, other way around. The energy difference between the higher level and the lower, appears as photon energy.
Colour of fire depends on its temperature. Heat energy ionises atoms by exciting the electrons in them. When electrons emit energy they fall back into their lower energy states emitting energy of frequency f (E=hf), in this case it would be the frequency of orange light. As a fire gets hotter E increases causing light of a higher frequency to be emitted.
An electron has dropped from a higher energy state to a lower one. The photon emitted has precisely the same energy as was lost by the electron.
The electrons in the electric circuit excite the atoms of the diode efficiently, not much energy is wasted (in the form of heat).
A light-emitting Diode (LED) is a semiconductor device that converts electrical energy into light energy. When put into a circuit, the current only travels in one direction. The most commonly used LED emits red light.
Neon signs work by passing a current of electricity through an evacuated tube filled with a non-reactive gas like neon or xenon. As the electrical current heats the gas to a plasma state the plasma gives off a colored light unique to the gas inside.
by applying a voltage across the boundary of two semi-conductors electrons are forces to travel across the boundary. This boundary has a voltage drop and the electrons are required to lose a discrete amount of energy in crossing it. In the case of the light emitting diode, it is a energy in the range of visible light.