its attentuation not bandwidth as u may think....
attenuation
2
1024
If the number of levels is L, the maximum number of nodes N in a binary tree is N = 2L-1. For L = 5, N equates to 31 thus.
Depending on the topology, increasing the number of nodes in a LAN or segment will result in higher collisions, more attenuation of the signal, and less throughput of data.
Use the following formula: (2^n)-1. E.g., if the depth is 3, the number of nodes is (2^3)-1 = 8-1 = 7. Note that 7 is the maximum number of nodes, not the actual number of nodes. To count the actual nodes you must traverse the tree, updating an accumulator as you go.
populated segments a network segment that contains ends nodes,such as work stations. unpopulated segments a network segment that does not contain end nodes, such as workstations. Unpopulated segments are also called link segments.
A full binary tree of depth 3 has at least 4 nodes. That is; 1 root, 2 children and at least 1 grandchild. The maximum is 7 nodes (4 grandchildren).
A lower speed network such as a 10BaseT network can handle 1024 devices per segment; that is not the limitation on the entire network.
lamda /2
The height of a complete binary tree is in terms of log(n) where n is the number of nodes in the tree. The height of a complete binary tree is the maximum number of edges from the root to a leaf, and in a complete binary tree, the number of leaf nodes is equal to the number of internal nodes plus 1. Since the number of leaf nodes in a complete binary tree is equal to 2^h where h is the height of the tree, we can use log2 to find the height of a complete binary tree in terms of the number of nodes.
An internode is a portion of plant stem between nodes. An internodal segment is a portion of nerve fibre.
Yes, depending on the number of nodes added, the topology of the network, and how busy the nodes are.
Anti nodes are the points where standing wave have maximum amplitude.
A broadcast to all the nodes on its segment