0
50ml = .05L of HCL
1.0 M = 1mol / 1L of HCL
simply multiply -
.05 by 1.0, and get your answer!
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How many moles of HCl are on 10 grams of substance?
The answer is 0,274 moles.
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
How many moles of HCl are present in a 0.0250 L solution?
1. First, remember definition of M (moles), M = moles of species / L. 0.33 M = 0.33 moles HCl / L 2. Then, multiple your volume by the molar concentration: 0.33 moles HCl / L x 0.70 L = 0.231 moles HCl or you can say n=CONCENTRATION multiply by VOLUME(HCl) which gives 2310 mol HCl It's helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
One step at a time.1/103 = 0.001 M HCl, so.....Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )0.001 M HCl = X moles HCl/0.025 Liters= 2.5 X 10 - 5 moles HCl========================now, balanced eqiationNaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)= 10 -4 grams caustic soda needed==========================
How many moles of HCl are on 10 grams of substance?
The answer is 0,274 moles.
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
How many molecules of hcl are in 507 moles?
507 x (6.022 x 10^23)
How many moles of HCl are present in a 0.0250 L solution?
1. First, remember definition of M (moles), M = moles of species / L. 0.33 M = 0.33 moles HCl / L 2. Then, multiple your volume by the molar concentration: 0.33 moles HCl / L x 0.70 L = 0.231 moles HCl or you can say n=CONCENTRATION multiply by VOLUME(HCl) which gives 2310 mol HCl It's helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
What is the limiting reagent in a reaction?
The limiting reagent in a reaction is the reactant that runs out first. For example, if you are reacting 10 moles of HCl and 5 moles of NaOH, you will get 5 moles of H20, 5 moles of NaCl, and 5 moles of HCl, because the remaining HCl had nothing to react with. Therefore, the NaOH is the limiting reagent.
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
One step at a time.1/103 = 0.001 M HCl, so.....Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )0.001 M HCl = X moles HCl/0.025 Liters= 2.5 X 10 - 5 moles HCl========================now, balanced eqiationNaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)= 10 -4 grams caustic soda needed==========================
What is the minimum molarity of HCl when titrated with 18.6ml of NaOH?
First of all, it is HCl solution, more properly hydrochloric acid (that is HC l ). It is composed of hydrogen (H) and chlorine (Cl). The answer depends on the volume of the acid and the concentration of the alkali. Here is a sample calculation with some random values for the variables you have not given. If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the number of moles of NaOH equals the number of moles of HCl. 25 ml is equal to 0.025 liters, and since molarity is moles per liter we have: Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125 moles Moles of NaOH = moles of HCl = 0.0125 moles If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the molarity of the HCl is: 0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl
How many teaspoons in 50ml of blood?
10
How many moles of hcl are needed to react with 0.35 g of NAHCO3?
The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
How many moles of H plus ions are present in one liter of 2 M HCl?
To determine the number of moles of ions present in a known volume of solution, follow this example:HCl dissociates completely in water into H+ and Cl-, because this is a strong acid, and only strong acids, bases, and ionic compounds have the ability to dissociate completely.This means one equivalent of HCl will generate one equivalent of H+ and Cl- ions; the same number of moles of HCl will generate the same number of moles for H+ and Cl-HCl --> H+ + Cl-Now determine the number of moles in the volume of your solution. Remember that 1M is another way to say 1 mole/L.(2moles HCl/ 1L) x (1L) = 2 moles HClSince the equation states that 1 equivalent of HCl is 1 H+, the final answer is:(2moles HCl/ 1L) x (1L) x (1 mole H+/1mole HCl) = 2 moles H+
How do you test hydrochloric acid whether it is strong or weak?
What you are doing here is titration. You know you have a solution of HCl, but you do not know how much HCl is in it. For this you use something that can react with HCl (NaOH) and use an indicator to tell you when the reaction is complete. The reaction is pretty simple: HCl + NaOH --> H2O + NaCl You can see here that NaOH and HCl have a 1:1 mol relationship. So, lets find out how many moles of NaOH you used up with concentration = moles/volume 0.10 M NaOH = moles NaOH/ 0.0197 L NaOH solution Remember that M is in moles/L moles NaOH = 0.00197 moles Since you have a 1:1 relationship of NaOH with HCl, the 0.00197 mol applies to HCl as well. The next question works the same way, but backwards. Try doing it yourself if you understood the first part before reading my answer. Find out how many moles of HCl you have so you can find out how much moles of NaOH you need for the neutralization. 0.050 M HCl = n HCl / 0.020 L HCl soln n HCl = 0.001 mol HCl Remeber the 1:1 relationship, which gives you that n NaOH = 0.001 mol. Now all you need is the volume. 0.1 M NaOH = 0.001 mol NaOH/ Volume soln V = 0.01 L = 10 mL
