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2-
+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)
Sodium - it goes from oxidation number 0 to +1
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
Hydrogen has an oxidation number of 0 in H2. In compounds it is generally +1, the exception is when it is present as the hydride ion, H- , when has an oxidation state of -1
2-
the formula for an ionic compound that contains the elements magnesium and sulfur.Mg + H2 SO4 -> Mg SO4 + H2. .
Ammonium chloride
H2 has the oxidation number 'zero'
Hydrogen gas (H2) Oxidation number is 0. Hydrogen (H+) is +1.
+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)
H2 so4
H2SO4 has a total of 7 atoms: 2 hydrogen, 1 sulfur, and 4 oxygen.
The sulfate molecule (SO4) is heteroatomic.
7
Sodium - it goes from oxidation number 0 to +1
Reacted aluminum has a +3 charge. Sulfur is usually a -2 charge. Thus the equation would be 2 Al + 3 S --> Al2S3