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Ona Wuckert

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11y ago

HCN + H20 <-> H3o+ + CN-

Ka = 6.2 x 10^-10

ka = [h3o+][CN-]/[HCN] = x^2/0.1m

x^2 + 6.2 x 10^-10x - 6.2 x 10^-11

x = 7.87 x 10^-6

pH = -log[x] = -log[7.87x 10^-6 = 5.1

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1w ago

The pH of a 0.1 molar aqueous solution of HCl would be 1. HCl fully dissociates in water to form H+ ions, making the solution highly acidic.

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12y ago

- log(0.1 M)

= 1

14 - 1

= 13 pH

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9y ago

It is a weak base.So pH depends on Kb value.

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Q: The pH of a 0.1 molar aqueous solution of HCl would equal?
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