As the lamps are identical, and all three draw a current of 6 A, then each lamp must be drawing 2 A. So, with one of the lamps disconnected, the current drawn from the supply will reduce to 4 A.
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
If three identical bulbs are connected in parallel to a battery, all three bulbs would have equal brightness.Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that, in a parallel circuit, the voltage across each parallel element is the same.There are effectively 6 series circuits in this example - battery and A - battery and B - battery and C - A and B - A and C - and B and C. These six combinations are also parallel circuits, and they are also in parallel with each other.
12V. Every resistor in a parallel circuit shares the same voltage. It is the current that gets divided.
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
The voltage is unknown, because it depends on the impedance of each battery. Certainly, damage is going to be done, because there will be excessive current.
If each battery is identical, yes.
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
If three identical bulbs are connected in parallel to a battery, all three bulbs would have equal brightness.Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that, in a parallel circuit, the voltage across each parallel element is the same.There are effectively 6 series circuits in this example - battery and A - battery and B - battery and C - A and B - A and C - and B and C. These six combinations are also parallel circuits, and they are also in parallel with each other.
parallel
Two batteries can supply more current than one if they are connected in parallel.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
more current will be in case of parallel because in series combination resistence is greater with respect to parallel combination
12V. Every resistor in a parallel circuit shares the same voltage. It is the current that gets divided.
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
as the given cells have the same current flowing in through them (current flowing through the cells connected in series is equal to the current flowing when connected in parallel ) equate the formula's of cells connected in series and cells connected in parallel.thus by equating we get the value of the internal resistor as 2 ohms.
If each lamp is connected in parallel, then there are three 'paths' that draw current from the supply.
2 amps