as the given cells have the same current flowing in through them (current flowing through the cells connected in series is equal to the current flowing when connected in parallel ) equate the formula's of cells connected in series and cells connected in parallel.thus by equating we get the value of the internal resistor as 2 ohms.
This is the rate of flow of heat between the internal surfaces of the structure and the environmental temperature in the space, for each degree of deviation of that temperature about its mean value.
The condition for the terminal voltage across a secondary cell to be equal to its emf is when there is no current flowing through the cell. When there is no current, there is no voltage drop across the internal resistance of the cell, and thus the terminal voltage equals the emf.
Internal temperature is the temperature at or near the center of an object. The internal temperature is very important in cooking things like roasts, chickens, turkeys, etc. There are situations where outside temperature may be quite warm, but internal temperature may be quite cool. Things are to be cooked until the internal temperature is hot, often for some period of time.
The resistance of a mineral to being scratched is known as its 'hardness'. This is a relative measurement determined by whether it scratches, or is scratched by, other materials of determined hardness. Hardness is measured on the Mohs scale. To give to some idea, diamond (the hardest known mineral) is a 10, while talc (the softest) is 1. A copper coin is around 3, a fingernail is around 2, an iron nail is around 5. Quartz, for example, is a 7.
The internal environment is important for development because it provides the necessary conditions for growth and functionality. It includes factors such as nutrients, temperature, pH, and oxygen levels, which directly impact the way organisms function and develop. A stable internal environment, known as homeostasis, is crucial for maintaining the proper functioning of cells and tissues, ultimately enabling growth and development to occur efficiently.
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
Internal resistance is approximately equal to 94.667
The flowing of electricity (amperage) is governed by the internal resistance of the connected device.
If Rin = Rout, then the voltage at the output of the device goes down to half of the value that the circuit has without the external resistance. Scroll down to related links and look at "Interconnection of two audio units".
"In short, it is 0.055555555555555555555555555555556OhmsYou can use ohms law to calculate this.You will use the formula: Resistance Equals Voltage Divided by Current.It is written: R=V/ISo use the numbers you provided, and the formula above.1.5 / 27 = 0.055555555555555555555555555555556"I dispute this answer. emf = I(R+r) is the actual equation u need. From this equation, u will find that V = emf - Ir. Ohm's law is not applicable for this situation. However I do think you will need a voltage to find the internal resistance.
This question can be answered using voltage dividers. Assume the power supply consists of a voltage source and a resistor. With no load, all of the voltage source's voltage is dissipated by the internal resistor of 15V. When there is a load, there are two resistors in series. To calculate the internal resistance:1. I=V/R. You know the 600ohm resistor dissipated 13.7V. So that would mean a current of 13.7/600=22.8mA2. If the 600ohm resistor dropped 13.7, kirchoff's voltage law would tell us the internal resistor dropped 15-13.7=1.3V.3. R=V/I, Use the current to calculate the internal resistance. 1.3/22.8mA = 56.9ohmsCommentFurther to the above answer, a voltage-source's voltage is not 'dissipated by the internal resistance when on no load'. On no load, there is no current passing through the internal resistance, so no 'voltage dissipation' can takes plac -i.e. the non-load voltage is 15 V.
Real-world batteries do not have zero internal resistance. When one connects a load (resistance) to a battery, current begins to flow and the open-circuit potential is divided between the battery's internal resistance and the resistance of the load. Thus, one will measure a lower voltage at the battery terminals when a load is connected, compared to no-load conditions.
It depends on the application. Voltmeters have a high internal resistance, while ammeters have a low internal resistance.
That will depend on the sum of the load resistance and the internal resistance of the battery (this is true for all power sources, not just 6 volt batteries). Small compact batteries tend to have higher internal resistance and therefore are more limited in the current they can deliver to a given load than larger batteries.
The behaviour you are describing is, in fact, due to the internal resistance of the voltage source.When a voltage source, such as a battery or generator, is not connected to a load, its potential difference is simply the electromotive force (or 'no-load voltage') of that source. When a load is connected, a load current flows not only through the load itself, but also through the internal resistance of the source. This causes an internal voltage drop across the internal resistance, which acts in the opposite sense (i.e. in accordance with Kirchhoff's Voltage Law), or direction, to the electromotive force, thus reducing the voltage available at the terminals. The greater the load (i.e. the lower the load resistance), the greater the resulting load current, and the greater the internal voltage drop -and the lower the terminal voltage.
No, it is desirable for a battery to have a low internal resistance.
The internal resistance of a device is the resistance in ohms of that device. It is the resistance electrons need to overcome before electricity is said to flow.