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To increase the rate of a reaction why would you increase the concentration of reactant?
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
What else can I help you with?
What concentration increase would cause a tenfold increase in the rate of a reaction of order 2?
For a second-order reaction, the rate of reaction is proportional to the square of the concentration of the reactant. Therefore, to achieve a tenfold increase in the reaction rate, the concentration must be increased by a factor of √10 (approximately 3.16). This is because if the concentration is increased by this factor, the rate will increase by (√10)² = 10.
How do concentrations affect rate according to the rate law?
The rate law describes the relationship between the concentration of reactants and the rate of a chemical reaction. Generally, an increase in the concentration of reactants will lead to a proportional increase in the reaction rate if the reaction is first order with respect to that reactant. For example, if the rate law is rate = k[A]^2, doubling the concentration of A would quadruple the reaction rate.
Why does increasing the concentration of a reactants increase the reaction rate?
Because it increases the probability of collisions
Which of these would be expected to increase the rate of sa chemical reaction?
Increasing temperature, increasing concentration of reactants, and adding a catalyst are all factors that can increase the rate of a chemical reaction. This is because they either provide more energy for the reaction to occur (temperature), increase the frequency of reactant collisions (concentration), or lower the activation energy required for the reaction to proceed (catalyst).
What would increase the concentration of reactants?
It means that there will be more particles of the reactants in the vessel, so they are more crowded and collisions of the right energy are more likely. or collisions of the right energy are more likely.
How does an equilibrium reaction respond to the addiof extra reactant?
The concentration or activity of the product(s) will increase, and if there is at least one other reactant than the added one that is required for the completion of the reaction, the concentration of such an unadded reactant will decrease. (If there were no available unadded reactant, the reaction would not technically have been in equilibrium at the start, even though it may have reached a steady state that can persist for a long time in the absence of changed conditions.)
TO INCrease the rate of a reaction why would you increase the concentration of the reactants?
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
How do you prove graphically that a reaction is first order?
To prove graphically that a reaction is first order, you would plot the natural log of the concentration of the reactant versus time. If the resulting graph is linear, then the reaction is first order. This linear relationship indicates that the rate of the reaction is directly proportional to the concentration of the reactant.
How does the rate law show how concentration changes change the rate of reaction?
The rate law equation relates the rate of a reaction to the concentrations of reactants. By examining the exponents of the concentrations in the rate law, one can determine how changes in the concentration of reactants affect the rate of the reaction. For example, if the exponent of a certain reactant is 2, doubling its concentration would quadruple the rate of the reaction according to the rate law equation.
In the reaction 2SO2 plus O2 Reversible 2SO3 which change would cause the greatest increase in the concentration of SO3?
Increasing the concentration of either SO2 or O2 would drive the reaction towards the formation of more SO3, resulting in an increase in the concentration of SO3. Increasing the temperature, however, would cause the greatest increase in the concentration of SO3 as it favors the forward reaction which produces more SO3.
What equation would calculate the rate constant from initial concentration?
The formula is:k(T) = ([A][B])/r where:- [A] and [B] are the concentrations of reactants- r is the reaction rate
What would happen to the rate of a reaction with rate law kNO2H2 if the concentration of NO were doubled?
The rate would be four times larger
