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F = ma

360 = 1200a

a = 0.3 m/s^s

a = (v-u)/t

(0.3)*(6) = v - 0

v = 18/10 m/s

momentum = mass*velcoity

p = m*v

p = 1200*(18/10)

p = 2160 kg m/s

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Q: Two men push on a stalled 1200 kg pickup giving it a net force of 360N for a time of 6 seconds What is the final momentum of the pickup?
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