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WHAT HAPPENS TO THE POWER OF THE RESISTANCE CONNECTED TO A BATTERY IS CUT IN HALF?
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Does miliamperes increase as does battery voltage when put in a series configuration?
The current in a circuit, expressed in milliamperes, is1,000 x (battery or power supply voltage)/(resistance connected between the power supply terminals)If you increase the voltage of the battery or power supply, the current in the circuitincreases proportionally, at least until something in the circuit gets hot, melts, fuses,and opens the circuit.
A 14point1 V battery is connected to a 142 resistor Neglecting the internal resistance of the battery calculate the power dissipated in the resistor Answer in units of W?
In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)
What is a resistor bank?
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
What is the resistance in a circuit if two 60ohm's resistors are connected in series?
The equivalent resistance of multiple resistors connected in series is the sum of theindividual resistances.(10 + 60 + 50) = 120 ohms for this particular trio of resistors in series.It makes no difference what battery they may be connected to, or if they're connected toany power supply at all.
What is meant by the internal resistance of a battery?
There is internal resistance in a battery because a battery is not an ideal voltage source. It may be close, but it is not ideal. As a result, analytically, there will be some series resistance, resistance which places a limit on the maximum current that the battery can provide. While no battery is ideal, most are sufficiently ideal to not require any consideration of the internal resistance. If your circuit is dependent on the internal resistance of a battery, then it is probably not well suited for that application.
When a battery is connected across a high resistance in parallel with a low resistance more power is dissapited in the low resistance Is this statement true or false?
true
What two factors determine the output energy of a battery?
The energy delivered by a battery would depend on-- the battery's voltage-- the resistance of the load connected across its output terminals-- the length of the time the load is connectedThe power delivered by the battery is [ (voltage)2 divided by (load resistance) ].The total energy delivered by the battery is [ (power) multiplied by (time the load is connected) ].
How much current does a size D battery have?
Doesn't work like that. Current drain is dependent on the (internal resistance of the battery and the) resistance/power requirements of what's connected to the battery. If shorted out, the current - unless the battery is fused or otherwise protected - can go into tens of amps.
When a multimeter is set to measure resistance?
it determines how well the current flows through the wires. ANSWER: When there is no outside power connected to it. But some power is necessary to read the resistance so the meter battery will supply the current necessary to measure the IR drop and translate that to resistance
How many amperes does a 6 volt DC battery put out?
That will depend on the sum of the load resistance and the internal resistance of the battery (this is true for all power sources, not just 6 volt batteries). Small compact batteries tend to have higher internal resistance and therefore are more limited in the current they can deliver to a given load than larger batteries.
What happens when metal wire is connected to a battery?
I believe it causes full power of battery flow to the neg. Where used photons of energy should be. Perhaps it gets hot enough then leaks?
What happens when a laptop put into sleep mode for a long time?
It will turn off. Because "sleeping" still takes power from the battery, unless the laptop is connected to the power source.
What would be the result if two batteries are connected in series in terms of power and voltage and current?
If two identical batteries were connected in series, the resulting voltage would double, the available current would remain the same, and the available power would double. Note that, by Ohm's Law and the Power Law, doubling the voltage into a set resistance would double the current and quadruple the power. This is inconsistent with the battery's ability to provide a certain current, so you would also need to double the load resistance, otherwise you could damage the battery.
What happens to the power of an electric circuit of the resistance is decreased?
if the resistance is decreased and the current stays the same, then the power decreases.
Does miliamperes increase as does battery voltage when put in a series configuration?
The current in a circuit, expressed in milliamperes, is1,000 x (battery or power supply voltage)/(resistance connected between the power supply terminals)If you increase the voltage of the battery or power supply, the current in the circuitincreases proportionally, at least until something in the circuit gets hot, melts, fuses,and opens the circuit.
What happens if you try to jump a fully charged battery?
Jumping a Fully Charged BatteryIF the connections [jumper cables] are connected properly, then nothing out of the ordinary happens. Connecting a jumper battery or power axillary power source only makes additional current available, if the starting circuit needs it. If the batteries are connected properly [in parallel] then this procedure increases the cranking Amps available and the voltage remains the same.
A 14point1 V battery is connected to a 142 resistor Neglecting the internal resistance of the battery calculate the power dissipated in the resistor Answer in units of W?
In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)
