The mass was conserved in the reaction of iron and sulfur. The law of conservation of mass states that mass is neither created nor destroyed. The weight of the beginning materials, iron and sulfur are exactly equal to the weight of the product, iron sulfide.
iron forms iron sulphide when reacts with sulphur, Fe + S = FeS in this reaction 32 g of sulphur require 56 g of iron so 16 g sulphur requires 28 g of iron.
It would depend on your definition of percentage. For example, if you were looking for percentage of atom count, you would count the atoms in the compound Fe2(SO4)3. You have 12 Oxygen, 3 Sulfur, and 2 Iron, leaving you with 3 sulfur out of 17 total atoms, or 3/17 or 0.176470588 (about 17.5%). If, on the other hand, you are talking about percentage of mass, then you must calculate the mass of each element in the compound. Iron's atomic mass is 55.847. Sulfur's atomic mass is 32.066. Oxygen's atomic mass is 15.999. Multiply these by their respective ratios. Iron (55.847*2=111.694) Sulfur (32.066*3=96.198) Oxygen (15.999*12=191.988) Add them together to get (111.694+96.198+191.988=399.88) Now, take the overall mass of the sulfur part (96.198) and divide it into the total mass (399.88). The answer is 96.198/399.88 or 0.24056717 or about 24%.
The percent by mass of iron in the stated compound is 100(17.6/27.9) or 63.1 %, to the justified number of significant digits. Since the compound contains only two elements, the percent by mass of sulfur is 100 - 63.1 or 36.9 %. To find the atomic percentages rather than the mass percentages, the mass for each element must be divided by the gram atomic mass of that element. 17.6 grams constitutes 17.6/55.457 or about 0.313 gram atoms of iron, and 10.3 grams of sulfur constitutes 10.3/32.06 or about 0.321 gram atoms of sulfur. The atomic ratios of the two elements in simple binary compounds such as iron sulfide must have ratios of small whole numbers. The specified compound contains about equal numbers of iron and sulfur and therefore has the formula FeS.
Sulfur is a non metallic element. Mass number of it is 32.
the percent sulfur by mass in so3 is 40.050%
Total mass before reaction=Total mass after reaction Proven by the law of mass conversion: Matter cannot be created or destroyed; it can only change forms.
Sulfur atomic mass: 32 a.m.e.Chlorine atomic mass: 35.5 a.m.e.Iron atomic mass: 56 a.m.e.
iron forms iron sulphide when reacts with sulphur, Fe + S = FeS in this reaction 32 g of sulphur require 56 g of iron so 16 g sulphur requires 28 g of iron.
While overall ENERGY has to be conserved, MASS does not. In a nuclear reaction mass can be converted into energy so the mass of the products may be less than the mass of the reactants. The difference in mass is converted into energy as Einstein's equation describes (E=MC squared). In a chemical reaction MASS has to be conserved.
When the only change in mass is converted to light. The amount of matter after the reaction does not change.
A piece of sulfur will burn and turn into ash, causing it to lose mass. A piece of of iron that burns will solidify and get heavier the hotter it gets. It gains mass because the make up of iron breaks down and turns into other compounds as it gets heated.
3.2g ..... assuming it is iron (II) Sulphide FeS2. The relative atomic mass of iron is 56, sulphur is 32, so the ratio of masses of these two elements IN THE FORMULA = 56 : 64. If 2.8g of iron was used then, from the ratio, this will react with 3.2g of sulphur.
1. Rusting is an oxidation reaction of iron.2. The mass of an object increase after rusting.
1. Rusting is an oxidation reaction of iron.2. The mass of an object increase after rusting.
It would depend on your definition of percentage. For example, if you were looking for percentage of atom count, you would count the atoms in the compound Fe2(SO4)3. You have 12 Oxygen, 3 Sulfur, and 2 Iron, leaving you with 3 sulfur out of 17 total atoms, or 3/17 or 0.176470588 (about 17.5%). If, on the other hand, you are talking about percentage of mass, then you must calculate the mass of each element in the compound. Iron's atomic mass is 55.847. Sulfur's atomic mass is 32.066. Oxygen's atomic mass is 15.999. Multiply these by their respective ratios. Iron (55.847*2=111.694) Sulfur (32.066*3=96.198) Oxygen (15.999*12=191.988) Add them together to get (111.694+96.198+191.988=399.88) Now, take the overall mass of the sulfur part (96.198) and divide it into the total mass (399.88). The answer is 96.198/399.88 or 0.24056717 or about 24%.
According to John Dalton matter can neither be created nor destroyed in a chemical reaction. The law of conservation ofass given by A Lavoisier suggest that total mass of products is equal to the the total mass of reactants .In other words there is no change in mass during a chemical reaction.
According to John Dalton matter can neither be created nor destroyed in a chemical reaction. The law of conservation ofass given by A Lavoisier suggest that total mass of products is equal to the the total mass of reactants .In other words there is no change in mass during a chemical reaction.