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v=f*wavelength v=2*.5 v=1 m/s
This question can't be answered as asked. A string vibrating at its fundamental frequency has nothing to do with the speed of the produced sound through air, or any other medium. Different mediums transmit sound at different speeds. The formula for wavelength is L = S/F, were L is the wavelength, S is the speed through the medium and F is the frequency. Therefore, the wavelength depends on the speed of sound through the medium and directly proportional to the speed and inversely proportional to the frequency.
The wavelength of the standing wave is 3.00 m, that is double the string length of 1.50 m.
normal fundamental- 180 Hz (open- open) = 540 Hz at 3rd- f at 3rd= 3f' 540 =180 it's wavelength= v/f= 343/180= 1.9 L= 3/2 (wavelength)= 2.85 60% of this = 1.71= new wavelength v= f x wavelength 343/ 1.71= 200 Hz
increase the length of the string means decrease the tension in the string, therefore as the tension decreases the frequency will drop due to loosen of the string.
v=f*wavelength v=2*.5 v=1 m/s
Wavelength = speed/frequency = 350/640 = 54.7 centimeters (rounded)
The wavelength is halved.
speed = frequency × wave_length → frequency = speed ÷ wave_length = 1.2 m/s ÷ 60 m = 50 Hz.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
This question can't be answered as asked. A string vibrating at its fundamental frequency has nothing to do with the speed of the produced sound through air, or any other medium. Different mediums transmit sound at different speeds. The formula for wavelength is L = S/F, were L is the wavelength, S is the speed through the medium and F is the frequency. Therefore, the wavelength depends on the speed of sound through the medium and directly proportional to the speed and inversely proportional to the frequency.
v = f h, h = lambda = wavelength. f = frequency in Hz v = velocity therefore, v = 1.5 * 440 (the units of v in this case are meters per second).
Question is to be corrected as to find the velocity of the sound waves Formula for velocity of the wave = frequency x wavelength Given frequency = 262 Hz and wavelength = 1.3 m So velocity = 262 x 1.3 = 340.6 m/s
Wavelength = velocity of sound in the medium / frequency Here velocity is not given. Let it be 330 m/s So required wavelength = 330/440 = 3/4 = 0.75 m
"Pressure" is not what causes strings to produce sound. It's "tension" which does that. Adjusting the tuners either increases or decreases the tension, thus altering the audible pitch. Bending the strings also increases the tension. The sound is due to the vibration of the strings. Greater tension causes a shorter, higher frequency wavelength or amplitude which produces a higher pitch. Lesser tension causes a longer, lower frequency wavelength which produces a lower pitch. Depressing the strings onto the fingerboard effectively shortens the length of the string. The more a string is shortened, the shorter its vibrational wavelength and the higher its frequency will become. The location along the fingerboard at which the string is depressed serves the same function as does the nut when a open string is sounded.
since v=f(lambda), where v is the speed in metres per second, f is the frequency in hertz and lambda the wavelength in metres , for this question, v= 440 x 1.5=660m/s
75 x 2 = 150 cm [wavelength = 2x part of string that it's vibrating] 150cm / 100 = 1.5m [convert to meters] 220s x 1.5m = 330m/s [speed] So in a way, your measuring is wrong due to the fact that you measured the whole string instead of the part that's vibrating after being plucked or bowed.