CH3-C(Br)(CH3)-CH3 + H2O = CH3-C(OH)(CH3)-CH3 + HBr
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
The chemical formula for Dextromethorphan Hydrobromide (HBr) is C18H25NO·HBr.
This equation is:HBr + LiOH = LiBr + H2O
2 HBr + Ba(OH)2-----------------------BaBr2 + 2 H2O
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
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The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
Al2O3 + 6HBr = 2Albr3 + 3H2O
The chemical formula of hydrobromic acis is HBr.
The chemical formula of hydrogen bromide is HBr.
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
The products are Potassium bromide(KBr), Water(H2O) and Carbon(CO2). KHCO3 + HBr ----> KBr + H2O + CO2