Remember Ohm's Law ; V = IR
That is volts = amps(current) X Resistance.
Algebraically rearrange
R = V/I
V = 20 volts
I = 200 mA = 200/1000 Amps = 0.2 amps.
Hence
R = 20 V / 0.2 Amps
R = 100 Ohms
The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.
voltage = current x resistance, so: voltage = 200 x 0.001 = 0.2 volts
V = I.R R = V/I R = 110/0.5 R = 220 Ohms
0.02 amperes
The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance. mistybabe r19 :DD
A short circuit = 0 ohm, from this one can use ohms law to calculate the current, that is E/R voltage divided by resistance as in this instance your resistance is zero and you can't divide by zero so your current will be infinit. In other words if your power supply is large enough to supply 200 amp, your current on a short circuit will be 200 amp.
If a circuit element has a voltage of 14V and a current of 70mA, then the resistance of the circuit element is 200 ohms. This is ohm's law. The resistance or type of the power supply is meaningless.
This is a class of current transformers, and is a fairly low class. This has to do with what kind of burden can be placed on the secondary. A general rule is a C200 current transformer can supply ~200 volts at full ratio to its' secondary. If the burden (the CT resistance + cable resistance + relay or instrument resistance) times the maximum expected current is higher than 200 volts, the CT is likely to saturate. During multiple fault events, a CT may keep some magnetizing current causing CT saturation to be higher on a reclose event. Typically CT's are sized and their ratios are chosen to minimize saturation when feasible.
Copper wire is recommended for a 200 amp service due to its higher conductivity and lower resistance compared to aluminum wire.
It is a voltage (potential) applied to a load that causes a current to flow through the load. Ohm's Law encapsulates this principal and states Volts = Current x Resistance. In your example, the applied voltage would be 200 volts.
100
200 ohm