voltage = current x resistance, so:
voltage = 200 x 0.001 = 0.2 volts
V = IR, so R = (V/I) = (2000 V / 200 A) = 10 Ohm
1400volts
8x12=96
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
This is necessary because a fuse is a protection against an overcurrent; excessive current produce melting.
Ohm's Law: Current = voltage divided by resistance. 5 V divided by 12 KΩ is 416 2/3 ma
The current will depend on external resistance - far better to consider total energy, conversion efficiency, or failing that, voltage. The answer will depend on device size anyway.
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.
Current, voltage and resistance are related by the Ohm's law formula which states that current is directly proportional to the applied voltage and inversely proportional to the resistance at a constant temperature. Stated mathematically: I = E/R where I = current in amperes, abbreviated to A E = voltage in volts, abbreviated to V R = resistance in ohms, usually signified by the Greek omega Ω
The voltage is gained by multiplying the current and resistance together, i.e.. 50 x 500 = 25000 Imagine the three as a triangle with the voltage at the top, and the current and resistance at the bottom- V . ---- . I x R The voltage divided by the current is the resistance and the voltage divided by the resistance is the current. Therefore the current times the resistance is equal to the voltage. Having any two of these figures allows you to find the third.
Copper can not of itself produce a current. <><><><><> However, resistance, be it copper or some other material, will produce a current if a voltage is applied to it. The rule is Ohm's law: Current = Voltage divided by resistance.
resistance does not produce currents . you need source (like voltage source , current source ,or , discharging capacitor) to generate current .
To produce 60 watts at 120 volts, you need 0.5 amps (Watts = Volts * Amps) At 120volts, a 240ohm resistor would produce 0.5 amps (Amps = Volts / Resistance) A 60 watt bulb will have a resistance of 240 ohms. Note that this is the resistance while the bulb is hot. You might measure a different resistance if you use an ohm meter because the filament is cold.
Mass
18volts
V = I x R so current I = 1/2 amp. I bet the bulb is rated at 60 W because Watts = Current x Voltage. Where V = voltage (volt) I = current (ampere) R = resistance (ohm) Your question isn't easy to answer. A lamp has two 'resistances': a 'cold' resistance, and a 'hot' resistance. Before it is energised, it is cold, so its resistance is low; when it is energised, it becomes very hot, and its resistance increases significantly. So, the question is whether your '240 ohms' is the cold resistance or the hot resistance. If it is the cold resistance, then a current of 0.5 A will flow through it for a fraction of a second, then its resistance will increase significantly, and the current will fall to a very much smaller value.
8x12=96
32v