200 ohm
5 ohms
20k is equal to 20,000 ohms (20 kilo ohms) and 200k is equal to 200,000 ohms (200 kilo ohms) of electrical resistance
Nine tenths of the voltage would appear across the 200-ohm coil.
A 10 ohm resistor across a 20 volt source has 2 amps flowing through it. A 20 volt source providing 2 amps is producing 40 watts. Voltage is Resistance times AmperesWatts is Voltage times AmperesAlternative AnswerDivide the square of the voltage by the resistance.
Ohm's Law Volts = Current x Resistance Amps = V / R 110 / 20 = 5.5 Amps
Remember Ohm's Law ; V = IR That is volts = amps(current) X Resistance. Algebraically rearrange R = V/I V = 20 volts I = 200 mA = 200/1000 Amps = 0.2 amps. Hence R = 20 V / 0.2 Amps R = 100 Ohms
200 is ten times as big as 20.
Total resistance is 120 ohms. The 120VAC will be split evenly over this 120 ohm load, so every ohm of resistance gets a volt. So there will be a 40 volt drop across the 40 ohm resistor.
5 ohms
A 1 ohm 20% tolerance resistor should not exceed 1.2 ohms actual resistance.
20k is equal to 20,000 ohms (20 kilo ohms) and 200k is equal to 200,000 ohms (200 kilo ohms) of electrical resistance
200 millimetres
5 A
The load voltage can be calculated using Ohm's Law: V = I * R, where V is the voltage, I is the current, and R is the resistance. Substituting the values, V = 2 mA * 10 k ohm = 20 V. Therefore, the load voltage will be 20 volts.
Nine tenths of the voltage would appear across the 200-ohm coil.
The resistivity of the material can be calculated using the formula: resistivity = resistance x cross-sectional area / length. Plugging in the values: resistivity = 20 ohm x 2 cm / 10 cm = 4 ohm cm. Since resistivity is measured in ohm meters (SI unit), the resistivity of the material in SI unit would be 0.04 ohm meter.
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.