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What is the resistance of a material that draws 200 mA of current at 20 V?

Remember Ohm's Law ; V = IR That is volts = amps(current) X Resistance. Algebraically rearrange R = V/I V = 20 volts I = 200 mA = 200/1000 Amps = 0.2 amps. Hence R = 20 V / 0.2 Amps R = 100 Ohms


Which is bigger 200 or 20?

200 is ten times as big as 20.


60 ohm and 40 ohm and 20 ohm resistors are all 3 connected in series across a 120VAC source what is the total voltage across 40 ohms resistance?

Total resistance is 120 ohms. The 120VAC will be split evenly over this 120 ohm load, so every ohm of resistance gets a volt. So there will be a 40 volt drop across the 40 ohm resistor.


What is the 20k and 200k setting on a digital ohm meter?

20k is equal to 20,000 ohms (20 kilo ohms) and 200k is equal to 200,000 ohms (200 kilo ohms) of electrical resistance


What is the upper control limit of a 1 ohm resistor with a 20 percent tolerance?

A 1 ohm 20% tolerance resistor should not exceed 1.2 ohms actual resistance.


What is the total resistance of a parallel circuit with four 20-ohm resisters?

5 ohms


What is bigger 200 millimetres or 20 centimetres?

200 millimetres


What will happen if the reading of ammeter a2 after passing through 30 ohm resistance if reading of a1 is 3A after passing through 20 ohm resistance if both are parallel to each other?

5 A


What will be the load voltage if load resistance is 10 k ohm and load current is 2 ma?

The load voltage can be calculated using Ohm's Law: V = I * R, where V is the voltage, I is the current, and R is the resistance. Substituting the values, V = 2 mA * 10 k ohm = 20 V. Therefore, the load voltage will be 20 volts.


What would be the result if a 24 volt 20-ohm low voltage contactor coil were wired in series with a 24 volt 200-ohm control relay coil?

Nine tenths of the voltage would appear across the 200-ohm coil.


A cylinder if material is 10 cm and has a cross section of 2 cm if its resistance along the length b 20 ohm what will be its resistivity in si unit?

The resistivity of the material can be calculated using the formula: resistivity = resistance x cross-sectional area / length. Plugging in the values: resistivity = 20 ohm x 2 cm / 10 cm = 4 ohm cm. Since resistivity is measured in ohm meters (SI unit), the resistivity of the material in SI unit would be 0.04 ohm meter.


There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?

Is the circuit in series or parallel? If series then R = R1 + R2 + R3 (where R = Resistance) Or R = 20+20+10 = 50 = 50 Ohms If parallel then I/R = I/R1 + I/R2 + I/R3 (where I = Volts and R = Resistance) Or 5 ohms

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