The bulb with the lowest resistance.
Current = Volts / Resistance
The starter motor can draw almost the full current capacity of the battery when it is running, fortunately it is rarely run for more than 10 to 15 seconds at a time.
As the lamps are identical, and all three draw a current of 6 A, then each lamp must be drawing 2 A. So, with one of the lamps disconnected, the current drawn from the supply will reduce to 4 A.
Yes it does as it is an Inductor and an Inductor needs to build up a magnetic field. It is called INRUSH current.
7.2 A
Current (amps)=Watts/Volts =2000/120 =16.75 =16.75 amps
YESAnswerNot necessarily. The current depends on the potential difference and the load resistance. If you connect cells in parallel, you do not effect its voltage or the load, so the current is unaffected (although the battery's current 'capacity' will increase). If you connect the cells in series, then you will increase the voltage and the current will increase.
No. Without a bulb there is no current draw.
As the lamps are identical, and all three draw a current of 6 A, then each lamp must be drawing 2 A. So, with one of the lamps disconnected, the current drawn from the supply will reduce to 4 A.
Draw a battery and light bulb. Draw a line from the smaller connector on the battery to the bottom of the light bulb, this is positive on both. Draw a line from the bigger connector on the battery to the side of the light bulb,'this is the negative of both. Looked all over and can't seem to find this one.
That does not depend directly on the brightness of the bulb, it depends on the current drawn by the bulb (which depends on the efficiency of the bulb). For example an incandescent bulb will draw much more current than a much brighter CFL bulb or LED bulb. Therefor switching to an brighter LED bulb can make the battery last much longer while switching to a brighter incandescent bulb will make the battery run down quicker.
The formulas you are looking for is I = E/R.
When you are wiring two light bulbs in SERIES, you split the voltage to each light bulb in HALF, meaning that it will only glow half the brightness per bulb, but it will only draw the current of one bulb, meaning if the bulbs were connected to a battery, it would last longer to connect them together in series, rather than parallel.
Without the battery hooked up, the current draw is too much for the alternator to keep fire on the plugs.
If each lamp is connected in parallel, then there are three 'paths' that draw current from the supply.
Check earth connection. Sometimes if wires aren't connected right, running the car will discharge the battery instead of charging it... ----------------------------------------- Check for a current draw by disconnecting the negative cable at the battery and hook a test light between the cable and the battery. Remove fuses until the light goes out. While doing so remember to depress the door jam switch as it will show a current draw.
yes because of bulb resistance :)
Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
it means battery can deliver 180 amperes per hour if driven at full load I.E, isa an application setup whican draw 180 amps is connected to a battery of 180 Ah it will delivery current till one hour . Chandra sekhar