999984
Another perspective:The above answer is, of course nonsense. since you only need to multiply 6X8, then anything LARGER than that, which is again multiplied by either 6 or 8 or both, becomes the next multiple. As there is no upper limit, you can keep going, making the question itself, nonsense. There is no "largest" number of any kind.600,000
<float_literals> -> <digit> { <digit> } [ . ] [ { <digit> } ] <digit> -> "0" | <digit excluding zero> <digit excluding zero> -> "1" | "2" | "3" | "4" | "5" | "6" | "7" | "8" | "9" hi dude i wish you are satisfied with my answer LOL ^^
Repeatedly divide the number by 8 until the number is zero. Take the remainders from each division (the remainders will always be in the range 0 to 7 inclusive). The first division finds the lowest-order digit, the last finds the highest-order digit. Example: Decimal value: 421 421 / 8 = 52 r 5 52 / 8 = 6 r 4 6 / 8 = 0 r 6 The remainders are 6, 4 and 5, so 421 decimal is 645 octal. To convert from octal to decimal, multiply each octal digit by 8^n, where n is the zero-based order of the digit (0 being the lowest order), then sum the products. Example: Octal number: 645 5 * (8^0) = 5 * 1 = 5 4 * (8^1) = 4 * 8 = 32 6 * (8^2) = 6 * 64 = 384 384 + 32 + 5 = 421 Note that n^0 = 1 for all n>=0.
int sum_digits (int num) { int sum; sum =0; while (num) { sum += num % 10; num /= 10; } return sum; } Example usage: int main (void) { int i; printf ("Input a 6-digit number: "); scanf ("%6d", &i); printf ("The sum of the digits in %d is: %d\n", i, sum_digits (i)); return 0; }
-- First of all, if the number is a fraction or a decimal, then don't worry about it. Only whole numbers are considered odd or even. -- All multiples of 2 are even numbers, and that's easy to recognize. It doesn't matter how big the number is, or how many digits it has. You only have to look at the last digit (the one on the right-hand end). If that digit is 2, 4, 6, 8, or 0, then the whole big number is even. Otherwise it's odd.
6 + c
The largest two-digit multiple of six is 96.
If two and three can go into that number,then it is a multiple of six. It is a multiple of six if BOTH of the following statements are true: 1) The last digit (ones place) is 0, 2, 4, 6, or 8. 2) When you add all the digits together, you get a multiple of 3. For example, 39 is not a multiple of 6 because the last digit is 9. But, 36 is a multiple of 6 because the last digit is 6 and 3+6=9 and 9 is divisible by 3.
The greatest six-digit number is 199,999.
The greatest six-digit number is 199,999.
It is a 4 digit multiple of 6.
The digit six in the number 10.596 represents six thousandths.
The largest 6 digit even number is 999998
The largest six digit number is 999,999.
54
The lowest 4-digit number that is divisible by 6 is 1002
There are an infinite number of multiples of 6 (numbers that six can divide into evenly with no remainder). Without using a calculator, you can determine if a number is a multiple of 6. To be a multiple of 6, it must have both 3 and 2 as factors. So if the number is even, then 2 is a factor. To determine if it is even, look at the ones digit, and if it is (0,2,4,6, or 8) then it's even. Then to determine if 3 is a factor, add the digits in the number, if this sum is a multiple of 3, then the number is also a multiple of 3 (or you could say 3 is a factor). If both of these are true, then the number is a multiple of 6. Example: 984: Last digit (ones digit) is 4, so it's even. Sum 9+8+4=21, which is a multiple of 3, so the number is a multiple of 3. Therefore it is a multiple of 6.
Any even number.