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Firstly divide percentages by molar mass of that element

C

65.45/12.01=5.45

H

5.45/1.01=5.40

O

29.09/16=1.82

Then divide the result of the first step by the smallest answer

C

5.45/1.82=3

H

5.40/1.82=3

O

1.82/1.82=1

Empirical Formula is C3H3O

If the molar mass is 110.1 we can divide this by our empirical formulas molar mass to get the molecular formula.

so 110.1/(12.01x3+1.01x3+16)=110.1/55.06=2

so the molecular formula is C6H6O2

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Q: What Hydroquinone is an organic compound It has a molar mass of 110.1 grams over mol and a composition of 65.45 percent C 5.45 percent H and 29.09 percent O by mass. What is the molecular formula?
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