CH3F is both liquid and solid noble gas solution.
Ch3f
The intermolecular forces (IMFs) that attract propane molecules to eachother is far weaker than the IMFs of ethanol molecules. Consequently there is less of an energy barrier for a propane molecule to evaporate. IMFs of propare are limited to the london dispersion forces, which are the weakest IMFs IMFs of ethanol are the london dispersion forces as well as the dipole-dipole interaction (- charge on oxygen and positive on hydrogen) and hydrogen bonding (very strong IMF)
CH3F contains no covalently bonded hydrogen atoms DIRECTLY to the Fluorine.
Yes.
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These are polar forces, intermolecular forces of attraction between molecules.
Yes, as there are no metals in this compound.
Yes. CH3F is the molecular formula of fluoromethane.
Metahne does not have a higher boiling point than methane. Fluoromethane, CH3F, has a boiling point of 195K, -78.2C, methane, CH4, has a boiling point of 109K approx -164 C. I make that fluoromethane has a higher temeprature boiling point than methane. This is what you would expect, London dispersion forces will be greater in CH3F as it has more electrons than CH4. CH3F is polar and there will be dipole dipole interactions which will not be present in CH4.
CH3F is polar. Check the differences in electronegativity
Dipole-dipole because the H is not connected with F IT would be H | H- C - F | H