Find moles HCl.
5 g HCl (1 mole HCl/36.450 grams)
= 0.1372 moles HCl
Now, Molarity = moles of solute/Liters of solution
Molarity = 0.1372 moles HCl/1 liter
= 0.1372 M HCl
Then.
-log(0.1372 M HCl)
= 0.9 pH ( you might call it 1, but pH can be off the scale )
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This is from the website linked to the left of this answer under Web Links:Solubility in water, g/100 ml at 20°C: 74.5Therefore, in 1 liter, 745.0 grams of CaCl2 will dissolve to make a saturated solution.
Dissolve 2 moles of the compound in enough water to make a final volume of 1 liter.
Salt forms a solution when added to water.
If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution, what is the molarity of the new solution?
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
9
This is from the website linked to the left of this answer under Web Links:Solubility in water, g/100 ml at 20°C: 74.5Therefore, in 1 liter, 745.0 grams of CaCl2 will dissolve to make a saturated solution.
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
sdfa
300.8
What volume of this solution do you desire? Let's say you want to make 1 liter of such a solution. You would weigh out 1 gram (1000 mg) of NaCl and dissolve it in enough water to make a final volume of 1 liter (1000 ml). Since 1000 ppm means 1000 mg/liter, this is how you make 1 liter of that solution. For larger or smaller volumes, adjust appropriately.
A normal solution is a solution in which 1 gram of solute is dissolved in 1 liter of water
0.1 N KCl is the same as 0.1 M KCl. This requires one to dissolve 0.1 moles per each liter of solution. The molar mass of KCl is 74.6 g/mol. So 0.1 moles = 7.46 gDissolve 7.46 g KCl in enough water to make 1 liter (1000 ml)Dissolve 3.73 g KCl in enough water to make 0.5 liter (500 ml)Dissolve 0.746 g KCl in enough water to make 0.1 liter (100 ml)etc., etc.
684 ml
Dissolve 2 moles of the compound in enough water to make a final volume of 1 liter.
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
Salt forms a solution when added to water.