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HYDROGEN
No, it is not a redox reaction. None of the oxidation numbers changes during the reaction. You have to determine the oxidation number for each element and see if it changes from reactant side to product side. If the oxidation number doesn't change, it is not a redox reaction.
an empirical formula For an ionic compound, the empirical formula is called a formula unit.
compound fraction
A compound number has 3 or more factors, two of the factors being 1 and the number itself.
1+ is the normal oxidation number for hydrogen
Hydrogen has an oxidation number of 0 in H2. In compounds it is generally +1, the exception is when it is present as the hydride ion, H- , when has an oxidation state of -1
Its oxidation number is -1, which is uncommon for hydrogen.
The oxidation number of hydrogen in KH is -1, because the only oxidation number for potassium in a simple inorganic compound is +1. A hydrogen atom can complete its outer electron shell by adding one electron acquire the electron configuration of helium, and this is what happens during the formation of alkali metal hydrides such as KH.
Usually the oxidation no of oxygen is -2 and the oxidation no of hydrogen is +1 in a compound.
When it has gained one electron, forming Hydride ions
2-
The oxidation number of a compound is zero (nitrogen -3, hydrogen +1, chromium +3, oxygen -2).
+1 for H, -1 for Cl
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
-1. The hydrogen is present as the anion, H-.
The oxidation number in sodium hydride are:Na +1 andH (in hydrides like this) it is -1