JK flip flop are synchronous ONLY when the rise or the fall edge of the clock will transfer the data to the outputs
JK flip flop are synchronous ONLY when the rise or the fall edge of the clock will transfer the data to the outputs
preset and clear
Because that is the definition of a latch. A J-K flipflop is master-slave triggered because that is the definition of a J-K flipflop. A D flipflop is edge triggered because that is the definition of a D flipflop.
tie both J & K high.
it is j-k flip flop
by combining j and k inputs we will get jk flipflop
library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity jkflipflop is Port ( clk, reset : in STD_LOGIC; q : inout STD_LOGIC; j : in STD_LOGIC; k : in STD_LOGIC; qn : out STD_LOGIC); end jkflipflop; architecture Behavioral of jkflipflop is begin process(clk,j,k,q) begin if(clk'event and clk='1')then if (reset = '1') then qn<='0'; else qn<=(j and(not(q)))or(q and(not(k))); End if; end if; end process; end Behavioral;
For a J-K flip-flop to set the output Q upon the active clock transition (typically the rising edge), the conditions are that the J input must be high (J = 1) and the K input must be low (K = 0). This combination ensures that when the clock triggers, the flip-flop will set Q to 1. If both J and K are low, or if J is low and K is high, the output Q will either remain in its current state or reset, respectively.
D Flip flop which have driven the output as the given input there is no change in the I/O. But in the case of T-Flipflop the output is inverted to the given input .i.e complement of the input is output. Thank you i am meganathan...
that kevin new that he wasnt going to live long but he kept trying
#include int main(){int num[100];printf("please input your numbers.enter any letter for the end\n");int i=0,j=0,k=0;while(scanf("%d",&num[i++]));i--;printf("you input %d numbers\n",i);for(j=i-1;j>=0;j--){for(k=0;knum[k+1]){int temp;temp=num[k+1];num[k+1]=num[k];num[k]=temp;}}}for(j=0;j
K j equals j when K is 1 or j is 0.