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To determine the number of moles in 56.3 grams of Li2SO4, you need to know the molar mass of Li2SO4 which is approximately 109.9 g/mol. Use the formula: moles = mass/molar mass. Therefore, moles = 56.3 g / 109.9 g/mol = 0.512 mol.
This reaction is:MgSO4 + 2 LiOH = Mg(OH)2(s) + Li2SO4
Yes. Is two Li+ and one SO4-2 ions which dissociate in aqueous solution.
Lithium Sulfate Li2SO4 has 4 oxygen atoms per molecule.
You would start by simply writing your reactants and products out, noting this is a double replacement reaction. BaCl2 + Li2SO4 -----> BaSO4 + LiCl Then you would need to go back and balance the equation. Note in the above that there are two chloride ions on the left but only one on the right. This can be balanced by placing a coefficient of 2 in front of LiCl. BaCl2 + Li2SO4 -----> BaSO4 + 2LiCl This is now a balanced equation.
1, 1, 1, 1
Li2SO4
lithium sulphate
Li2SO4
+6
Lithium sulfate
Lithium sulfate
The formula for lithium sulfate is Li2SO4.
Yes
The formula is: Li2S the "2" is a subscript
The reaction is: Li + 2 S = Li2S (lithium sulfide)
Here's that equation:H2SO4 + 2LiOH => Li2SO4 + H2OAnd gee, it's even a load of bollocks ;DH2SO4 + 2LiOH => Li2SO4 + 2H2OThere, if you didn't put the 2 in front of water than you would get 4 hydrogen on one side and 2 oxygen while the other side would only have 2 hydrogen and one oxygen.I believe the technical term for that correction is Pwned.