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Many three letter words can be formed from the letters of the word Philippines. These includes pip, sin and pin.
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What is the distinct letter in the word humility?
humility distinct letters
What are distinct letters?
dictinct object or letters- It implies that each object or letters differs in some way from the every other object or letters in the set Ex. Banana=B,a,n distinct letters
How many distinct ways can the letters of the word ROBBER be arranged?
180
How many distinct arrangements can be made with the letters in the word BOXING?
The number of distinct arrangements of the letters of the word BOXING is the same as the number of permutations of 6 things taken 6 at a time. This is 6 factorial, which is 720. Since there are no duplicated letters in the word, there is no need to divide by any factor.
How many ways can the letters of the word meddles be arranged?
In how many distinct ways can the letters of the word MEDDLES be arranged?
What are silent letters on the word punctuation?
In the word "punctuation," the silent letters are "u" and "a." The "u" is silent, as it is not pronounced in the word. The "a" is also silent, as it does not have a distinct sound in the word.
How many distinct arrangements can be made with the letters in the word banana?
There are 6!/(3!*2!) = 60 arrangements.
How many distinct ways can the letters in the word Google be arranged?
6 x 5 x 4 x 3 x 2/2 = 360 distinct ways
How many ways can the letters of the word china be arranged?
Since all letters are distinct, there are 120.1x2x3x4x5=120, not 5. CHINA=5 letters. So do the same formula (1x2x3x4x5) but the answer is 120.
How many permutations of the letters in the word Louisiana are there?
The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.
How many arrangements can be made with the letters spineless?
The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240
How many distinct arrangements can be made with the letters in the word surprising?
Take note of the word "surprising":There are 10 letters total.There are 2 r's.There are 2 i'sThere are 2 s's.There are 10! total ways to arrange the letters. Since repetition is not allowed for the arrangements, we need to divide the total number of arrangements by 2!2!2! Therefore, you should get 10!/(2!2!2!) distinct arrangements
